用Python校验身份z号码真伪

#这个算法都给了，应该比较简单吧。我也很菜，随意写了一个。异早衡常没做，你可以自##己加一下。做一些验证过滤。不知道随机是不是真是随意随机，我没有按照身份z规##则做随机。是真的随机了18位。。。 如果你有规则，也可以自己写一个。

import random

yushu=[x for x in range(0,11)] 

ma=['1','0','X','9','8','7','6','5'陆饥做,'4','3','2','1']

def yanzheng(nid):

dicma=dict(zip(yushu,ma))

sum=0

for x,y in enumerate(nid[:-1]):

sum+=((2**(18-x-1))%11)*int(y) #17位对应系数相乘的和

    if nid[-1]==dicma[sum%11]: #校验码对照

    return '%s True'%nid

    else:

    return '%s False'%nid

def readfile(fname):

f=open(fname,'rb')

for line in f.readlines():

print  yanzheng(line.strip())

f.close()

def randnum():

idstr=''

for i in range(17): #前17位随机

idstr+=str(random.randint(0,9))

idstr+=random.choice(ma) #最后一位从列表种随意一个，因为有X

return idstr

if __name__=="__main__":

nid=raw_input('Please enter your ID: ') #用户输入ID，没做任何验证

print yanzheng(nid)  #验证身份z

readfile('id.txt')   #从文件读出来 再验证

print yanzheng(randnum())  肢册#随机一个 在验证

area={"11":"北京","12":"天津","13":"河北","14":"山西","15":"内蒙古","21":"辽宁","22":"吉林","23":"黑龙江","31":"上海","32":"江苏","33":"浙江","34":"安徽","35":"福建","36":"江西","37":"山东","41":"河南","42":"湖北","43":"湖南","44":"广东","45":"广西","46":"海南","50":"重庆","51":"四川","52":"贵州","53":"云南","54"裤段返:"西藏","61":"陕西","燃御62":"甘肃","63":"青海胡饥","64":"宁夏","65":"新疆","71":"台湾","81":"香港","82":"澳门","91":"国外"}

s=input('输入身份z号码：')

t=s[0]+s[1]

print(area[t])

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