用动态扫描方法在六位数码管上显示出稳定的654321怎么我用proteus仿真出问题,下面是我的程序和仿真图

用动态扫描方法在六位数码管上显示出稳定的654321怎么我用proteus仿真出问题,下面是我的程序和仿真图,第1张

仿真试试这样消御歼闷祥隐(实物不能这样),下面只写出1的,其它的类同:

dula=1

P0=table[one] //送段数据

dula=0

//P0=0xff //送位数据前关闭所有显示,防止打开位选锁存后段选数据通过位选锁镇罩冲存器

wela=1

P0=0xfe

wela=0

delay(1)

P0=0x00// 消隐

淘bao 旺铺: 广州局悉华电 单片机学习板 单片机外围学习模块/传感器模块

//4*4键盘检测程序,按下键后相应的代码显示在数码管上

#include<reg51.h>

sbit beep=P2^3

sbit dula=P2^6

sbit wela=P2^7

unsigned char i=100

unsigned char j,k,temp,key

void delay(unsigned char i)

{

for(j=ij>0j--)

for(k=125k>0k--)

}

unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,

0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71}

display(unsigned char num)

{

P0=table[num]

dula=1

dula=0

P0=0xc0

wela=1

wela=0

}

void main()

{

dula=0

wela=0

while(1)

{

P3=0xfe

temp=P3

temp=temp&0xf0兄腊册

if(temp!=0xf0)

{

delay(10)

if(temp!=0xf0)

{

temp=P3

switch(temp)

{

case 0xee:

key=0

break

case 0xde:

key=1

break

case 0xbe:

key=2

break

case 0x7e:

key=3

break

}

while(temp!=0xf0)

{

temp=P3

temp=temp&0xf0

beep=0

}

beep=1

display(key)

P1=0xfe

}

}

P3=0xfd

temp=P3

temp=temp&0xf0

if(temp!=0xf0)

{

delay(10)

if(temp!=0xf0)

{

temp=P3

switch(temp)

{

case 0xed:

key=4

break

case 0xdd:

key=5

break

case 0xbd:

key=6

break

case 0x7d:

key=7

break

}

while(temp!=0xf0)

{

temp=P3

temp=temp&0xf0羡宏

beep=0

}

beep=1

display(key)

}

}

P3=0xfb

temp=P3

temp=temp&0xf0

if(temp!=0xf0)

{

delay(10)

if(temp!=0xf0)

{

temp=P3

switch(temp)

{

case 0xeb:

key=8

break

case 0xdb:

key=9

break

case 0xbb:

key=10

break

case 0x7b:

key=11

break

}

while(temp!=0xf0)

{

temp=P3

temp=temp&0xf0

beep=0

}

beep=1

display(key)

}

}

P3=0xf7

temp=P3

temp=temp&0xf0

if(temp!=0xf0)

{

delay(10)

if(temp!=0xf0)

{

temp=P3

switch(temp)

{

case 0xe7:

key=12

break

case 0xd7:

key=13

break

case 0xb7:

key=14

break

case 0x77:

key=15

break

}

while(temp!=0xf0)

{

temp=P3

temp=temp&0xf0

beep=0

}

beep=1

display(key)

}

}

}

}

#include <reg52.h>

#define uchar unsigned char

#define uint unsigned int

sbit A = P2^5

sbit B1 = P2^6

sbit C = P2^7

uchar code lie[]={1,2,4,8,16,32,64,128}

uchar code DIS1[]=

{

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xF7,0xE3,0xC1,0x80,0xE3,0xE3,0xE3,0xE3, /*箭头*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff

}

uchar code DIS2[][8]=

{

0xC3,0xBD,0xBD,0xBD,0xBD,0xBD,0xBD,0xC3,/*"未命名文件",0*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xFF,0xEF,0xE7,0xEF,0xEF,0xEF,0xC7,0xFF,/*"未命握梁哪名文件",1*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xC7,0xBB,0xBF,0xBF,0xCF,0xE7,0xFB,0x83,/*"未命名文件",2*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xC7,0xBB,0xBF,0xBF,0xCF,0xBF,0xBB,0xC7,/*"未命名文件",3*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xDF,0xCF,0xD7,0xDB,0xDD,0x81,0xDF,0xDF,/*"段码未命名文件",4*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0x83,0xFB,0xFB,0xC3,0xBF,0xBF,0xBB,0xC7,/*"未命名文件",5*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xFF,0xC7,0xBB,0xFB,0xC3,0xBB,0xBB,0xC7,/*"未命名文件",6*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xFF,0x83,0xBF,0xDF,0xEF,0xF7,0xF7,0xF7,/*"未命名文件",7*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xFF,0xC7,0xBB,0xBB,0xC7,0xBB,0xBB,0xC7,/*"未命名文件",8*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

0xFF,0xC7,0xBB,0xBB,0x87,0xBF,0xBF,0xC7,/*"未命名文件",9*/

0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,

}

void Delay_Ms(uchar ms)

{

uchar x,y

for(x=0x<msx++)

for(y=0y<110y++)

}

void display()

{

uchar i,j,k

for(j=0j<sizeof(DIS2)j++)

for(k=0k<20k++)

for(i=0i<8i++) //8列渣乱显示

{

A=0B1=1C=1

P0 = lie[i]

A=1B1=1C=1

P0 = DIS1[i+j]

Delay_Ms(15)

A=1B1=1C=1

P0 = 0xff

}

}

void main()

{

A=1B1=0C=1

P0=0

while(1)

{

display()

}

}

按键那里我们没有程序在,点阵驱动做好了加上按键就switch上去就好了!


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原文地址: http://outofmemory.cn/yw/12493619.html

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