用C语言编一个程序,使给出一个数的原码,求得反码，补码。

#include<stdio.h>

int main(){

int i,j,k

int a[16], af[16], ab[16]//af存储反码，ab存储补码第0位为符号位

char b[16]

scanf("%s", b)

for(i = 0b[i] != '\0'兄团睁i++){

a[i] = b[i] - '0'

}

j = i-1

ab[0] = af[0] = a[0]//符号位始终不变

if(a[0] == 1){//当从屏幕输入的是负数，则作相应变换

for(i = ji >0i--){

af[i] = 1 - a[i]

ab[i] = a[i]

if(a[i] == 1){

i--

break

}

}

k = i

for(i >0i--)

af[i] = 1 - a[i]

for(i = ki >0i--)//补码从末位数起第一个不为0，以后均取反

ab[i] = 1 - a[i]

}

else{//如果是正数，则全部复制

for(i = ji >0i--){//正数反码、补码都与原码相同

af[i] = a[i]

ab[i] = a[i]

}

}

printf("对应的反码羡岁是：\n")

for(i = 0i <= ji++)

printf("%d", af[i])

printf("\n")

printf("对应的补码是：\n")

for(i = 0i <= ji++)

printf("%d", ab[i])

}

在vc下编译测试通过。另，本代码未考虑输入非或和法问题，所输入的数字智能由1和0组成

Private Sub Command1_Click()

Dim a(16) As Integer, x As Integer

x = CInt(Text1.Text)

If x >= 0 Then a(16) = 0 Else a(16) = 1

x = Abs(x)

For i = 1 To 15

  a(i) = x Mod 2

  x = x \ 2

Next i

Text2.Text = ""

For i = 16 To 1 Step -1

  Text2.Text = Text2.Text &a(i)

Next i

If a(16) = 0 Then

  Text3.Text = Text2.Text

  Text4.Text = Text2.Text

  Exit Sub

End If

For i = 1 To 15

  a(i) = 1 - a(i)

Next i

Text3.Text = a(16)

For i = 15 To 1 Step -1

  Text3.Text = Text3.Text &a(i)

Next i

Text4.Text = a(16)

a(1) = a(1) + 1

i = 1

While a(i) = 2 And i <15

  a(i) = 0

  a(i + 1) = a(i + 1) + 1

  i = i + 1

Wend

For i = 15 To 1 Step -1

  Text4.Text = Text4.Text &a(i)

Next i

End Sub

#include<iostream.h>

main()

{ 

 char cc[8]

 int a[8],b[8],i,j,c=0

 for(i=0i<8i++)

  {

  cin>> cc[i]

  a[i]=b[i]=cc[i]-48 

  }

 if(a[0]==1)

 {

  cout<<"原码为:"

 for(i=0i<8i++)//原码

  cout<<a[i] 

  cout<<"反码为:"

 cout<< "1" 

 for(i=1i<8i++)//负数反补不同 

  {

  if(a[i]==0) //反码 

   cout<<"1"

  else

   cout<<中空枝"0"

  } 

 cout<<"补码为:"

 cout<< "1" 

  if(b[7]==0) 

  {b[7]=0c++}

 if(c)

 {

  for(i=1i<7i++) 

  {

  if(b[i]==0) 

   b[i]=1

  else

   b[i]=0

  } 

  b[7]=0

  b[6]++ 

  for(i=6b[i]==2i--)

  {

   b[i]=0

   b[i-1]++ 亏指

  } 

 

  for(i=1i<8i++)

   cout<<b[i] 

  

 } 

 else 

 {

 for(i=1i<卖敏7i++) 

  {

  if(a[i]==0) 

   cout<<"1"

  else

   cout<<"0"

  } 

 cout<<"1" 

 } 

 }

 else

 {

 cout<<"原码为:"

 for(i=0i<8i++)//正数原反补一样 

  cout<<a[i]

 cout<<"反码为:"

 for(i=0i<8i++)

  cout<<a[i]

 cout<<"补码为:"

 for(i=0i<8i++)

  cout<<a[i]

 }

}

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