求一个列换位加密的C语言算法！！！谢谢各位大佬了！！

#include <stdio.h>#include <stdlib.h>#include <稿仔肆math.h>戚胡#include <string.h>const int MAXSIZE = 100char *encrypt(char *essay) {int i,j,n,u,v,m,len = strlen(essay) char *result m = n = (int)sqrt(len) if(m * m <len) ++n result = (char *)malloc(m * n * sizeof(char) + 1) for(i = 0i <m++i) {for(j = 0j <n++j) {u = n * i + j v = m * j + i if(u <len) result[v] = essay[u] else result[v] = ' ' }}result[m * n] = 0 return result} int main() {char s[MAXSIZE],*u printf("输入明文:\n"键轿) fgets(s,MAXSIZE,stdin) s[strlen(s) - 1] = 0// 去除尾部的\nu = encrypt(s) printf("密文是:\n%s\n",u) free(u) return 0}

给你，拆态自己再稍微改造一下吧：

#include "stdio.h"

#include "conio.h"

main()

{

int k,i=0

char a[100],b[100]

printf("qing shu ru ni de mi wen \n"旅派源)

gets(a)

printf("qing shu ru mi shi \n")

scanf("羡袜%d",&k)

printf("\n")

do{

b[i]=(char)(a[i]+k)

if(b[i]>122){

b[i]=(char)(b[i]-26)

}

i++

}while(a[i]!='\0')

puts(b)

getch()

}

#include <stdio.h>

#include <string.h>

void main()

{

int i,nchar str[21]

gets(str)n=strlen(str)

if(n==0) printf("error")

for(i=0i<ni++)

if((str[i]<'a'||str[i]>'z')&&谨亮(str[i]<'A'||str[i]>'Z'))

printf("error")

else

{

for(i=0i<尘好ni++)

{

if((str[i]>='派晌铅x'&&str[i]<='z')||(str[i]>='X'&&str[i]<='Z'))

str[i]-=22

else str[i]+=4

printf("%c",str[i])

}

}

}

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