C语言编程计算利息

#include

int main()

{

double m,sum//m借钱数 sum终利息本金颂旁

int i=0

printf("请输宏仿入借钱数野绝橡：")

scanf("%lf",&m)//float应%f,double应%lf,int应%d

sum=m

for( i=0i<30i++ )

{

m *= 0.0005 //借款*利率

sum += m //借款余额

m=sum

}

printf("30利息：%lf\n",sum)

return 0

}

我刚写档岁的，希望对你有所帮助。

#include<stdio.h>

double BenXi(int year,double money)

int main()

{

int year

double money,benxi

do

{

printf("please input the years you save money and the amounts of money:\n")//输入存指耐期和存款额

scanf("%d%lf",&year,&money)

}while(year>5||year<行逗睁1||money<=-0.0000000001)

benxi=BenXi(year,money)

printf("%lf\n",benxi)

return 0

}

double BenXi(int year,double money)

{

double lilv=0

double benxi

switch(year)

{

case 1:lilv=2.25/100break

case 2:lilv=2.7/100break

case 3:lilv=3.24/100break

case 5:lilv=3.6/100break

default:break

}

benxi=money*(1+lilv)

return benxi

}

以下程序行尺亏就能完成档神任务了

/*

输入存款金额

money、存期

year

和年利率

rate，根据下列公式计算存款到期时的利息

interest(税前)，输出时保留2位小数。

interest

=

money(1+rate)^year

-

money

输入输出示例：括号内为说明

输入

1000

3

0.025

(money

=

1000,

year

=

3,

rate

=

0.025)

输出

interest

=

76.89

*/

#include

#include

int

main(void)

{

int

money,

year

double

interest,

rate

//printf("type

in

money:")

scanf("%d",&money)

scanf("%d",&year)

scanf("%lf",&rate)

interest

=

money

*

pow((1+rate),year)

-

money

//pow就是计算x^y的函数

printf("interest

=

%.2f\困罩n",

interest)

}

---