汇编语言循环程序设计，怎么复制和排序？

ASSUME DS:seg1, CS:seg2\x0d\x0a\x0d\x0aseg1 SEGMENT\x0d\x0afirst DB 5,-8,3,9,-2,-5,7,-9,0,5,4,9,-6,1,-1,8,-3,6,2,-7,0,-4\x0d\x0aLEN_first EQU $ - first\x0d\x0a\x0d\x0asecond DB 30 DUP(?)\x0d\x0a\x0d\x0aseg1 ENDS\x0d\x0a \x0d\x0aseg2 SEGMENT\x0d\x0astart:\x0d\x0aMOV AX, seg1\x0d\x0aMOV DS, AX\x0d\x0a--------------------------下面是复制\x0d\x0a\x0d\x0a2.复制\x0d\x0a将first行中的非负数复制到second行\x0d\x0a\x0d\x0aMOV SI, 0\x0d\x0aMOV DI, 0\x0d\x0aMOV CX, LEN_first\x0d\x0aLOP:\x0d\x0aMOV AL, first [SI]\x0d\x0aCMP AL, 80H\x0d\x0aJNB NEXT\x0d\x0aMOV second [DI], AL\x0d\x0aINC DI\x0d\x0aNEXT:\x0d\x0aINC SI\x0d\x0aLOOP LOP\x0d\x0a\x0d\x0a--------------------------下面是排序\x0d\x0a\x0d\x0a3.排序\x0d\x0a将second行中的数据按升序重新排列。\x0d\x0a\x0d\x0aMOV CX, DI\x0d\x0aDEC CX\x0d\x0aLP1:\x0d\x0aPUSH CX\x0d\x0aMOV SI, 0\x0d\x0aLP2:\x0d\x0aMOV AL, second [SI]\x0d\x0aCMP AL, second [SI + 1]\x0d\x0aJB NEXT2\x0d\x0aXCHG AL, second [SI + 1]\x0d\x0aMOV second [SI], AL\x0d\x0aNEXT2:\x0d\x0aINC SI\x0d\x0aLOOP LP2\x0d\x0aPOP CX\x0d\x0aLOOP LP1\x0d\x0a\x0d\x0a--------------------------下面是结束程序\x0d\x0a\x0d\x0aEXIT:\x0d\x0aMOV AH, 4CH\x0d\x0aINT 21H\x0d\x0a\x0d\x0aseg2 ENDS\x0d\x0aEND start

assume

cs:code,ds:data

data

segment

bcd

db

01h,23h,45h,67h,89h,13h,24h,35h,46h,57h

bcd码

asc

db

20

dup(0)

转换之后存在这里

data

ends

code

segment

start:

mov

ax,data

mov

ds,ax

mov

cx,10

循环次数

lea

si,bcd

si指向bcd码

lea

di,asc

di指向转换之后的目标位置

next:

mov

al,[si]

取出bcd码

mov

dl,al

放dl保存

and

al,0fh

去掉高4位，先处理低位的bccd码

or

al,30h

转换成ascii码

mov

[di],al

存到目标位置

inc

di

修改目标地卖悔址指针

push

cx

要用到移位指令，需要cl寄存器，所以将循环次数进栈保存

mov

cl,4

移动4位滚配让

shr

dl,cl

将大局原bcd码的高位移到地4位上

or

dl,30h

转换成ascii码

mov

[di],dl

存入目标位置

inc

di

修改地址指针

inc

si

修改地址指针

pop

cx

循环次数出栈

loop

next

循环

mov

ax,4c00h

int

21h

code

ends

end

start

木西？我喜欢这名字

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