!高分跪求帮忙写一个简单小程序的JAVA课程设计报告(内详!!)

!高分跪求帮忙写一个简单小程序的JAVA课程设计报告(内详!!),第1张

连连看java源代码

import javax.swing.*

import java.awt.*

import java.awt.event.*

public class lianliankan implements ActionListener

{

JFrame mainFrame//主面板

Container thisContainer

JPanel centerPanel,southPanel,northPanel//子面板

JButton diamondsButton[][] = new JButton[6][5]//游戏按钮数组

JButton exitButton,resetButton,newlyButton//退出,重列,重新开始按钮

JLabel fractionLable=new JLabel("0")//分数标签

JButton firstButton,secondButton//分别记录两次被选中的按钮

int grid[][] = new int[8][7]//储存游戏按钮位置

static boolean pressInformation=false//判断是否有按钮被选中

int x0=0,y0=0,x=0,y=0,fristMsg=0,secondMsg=0,validateLV//游戏按钮的位置坐标

int i,j,k,n//消除方法控制

public void init(){

mainFrame=new JFrame("JKJ连连看")

thisContainer = mainFrame.getContentPane()

thisContainer.setLayout(new BorderLayout())

centerPanel=new JPanel()

southPanel=new JPanel()

northPanel=new JPanel()

thisContainer.add(centerPanel,"Center")

thisContainer.add(southPanel,"South")

thisContainer.add(northPanel,"North")

centerPanel.setLayout(new GridLayout(6,5))

for(int cols = 0cols <6cols++){

for(int rows = 0rows <5rows++ ){

diamondsButton[cols][rows]=new JButton(String.valueOf(grid[cols+1][rows+1]))

diamondsButton[cols][rows].addActionListener(this)

centerPanel.add(diamondsButton[cols][rows])

}

}

exitButton=new JButton("退出")

exitButton.addActionListener(this)

resetButton=new JButton("重列")

resetButton.addActionListener(this)

newlyButton=new JButton("再来一局")

newlyButton.addActionListener(this)

southPanel.add(exitButton)

southPanel.add(resetButton)

southPanel.add(newlyButton)

fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText())))

northPanel.add(fractionLable)

mainFrame.setBounds(280,100,500,450)

mainFrame.setVisible(true)

}

public void randomBuild() {

int randoms,cols,rows

for(int twins=1twins<=15twins++) {

randoms=(int)(Math.random()*25+1)

for(int alike=1alike<=2alike++) {

cols=(int)(Math.random()*6+1)

rows=(int)(Math.random()*5+1)

while(grid[cols][rows]!=0) {

cols=(int)(Math.random()*6+1)

rows=(int)(Math.random()*5+1)

}

this.grid[cols][rows]=randoms

}

}

}

public void fraction(){

fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText())+100))

}

public void reload() {

int save[] = new int[30]

int n=0,cols,rows

int grid[][]= new int[8][7]

for(int i=0i<=6i++) {

for(int j=0j<=5j++) {

if(this.grid[i][j]!=0) {

save[n]=this.grid[i][j]

n++

}

}

}

n=n-1

this.grid=grid

while(n>=0) {

cols=(int)(Math.random()*6+1)

rows=(int)(Math.random()*5+1)

while(grid[cols][rows]!=0) {

cols=(int)(Math.random()*6+1)

rows=(int)(Math.random()*5+1)

}

this.grid[cols][rows]=save[n]

n--

}

mainFrame.setVisible(false)

pressInformation=false//这里一定要将按钮点击信息归为初始

init()

for(int i = 0i <6i++){

for(int j = 0j <5j++ ){

if(grid[i+1][j+1]==0)

diamondsButton[i][j].setVisible(false)

}

}

}

public void estimateEven(int placeX,int placeY,JButton bz) {

if(pressInformation==false) {

x=placeX

y=placeY

secondMsg=grid[x][y]

secondButton=bz

pressInformation=true

}

else {

x0=x

y0=y

fristMsg=secondMsg

firstButton=secondButton

x=placeX

y=placeY

secondMsg=grid[x][y]

secondButton=bz

if(fristMsg==secondMsg &&secondButton!=firstButton){

xiao()

}

}

}

public void xiao() { //相同的情况下能不能消去。仔细分析,不一条条注释

if((x0==x &&(y0==y+1||y0==y-1)) || ((x0==x+1||x0==x-1)&&(y0==y))){ //判断是否相邻

remove()

}

else{

for (j=0j<7j++ ) {

if (grid[x0][j]==0){ //判断第一个按钮同行哪个按钮为空

if (y>j) { //如果第二个按钮的Y坐标大于空按钮的Y坐标说明第一按钮在第二按钮左边

for (i=y-1i>=ji-- ){ //判断第二按钮左侧直到第一按钮中间有没有按钮

if (grid[x][i]!=0) {

k=0

break

}

else{ k=1} //K=1说明通过了第一次验证

}

if (k==1) {

linePassOne()

}

}

if (y<j){ //如果第二个按钮的Y坐标小于空按钮的Y坐标说明第一按钮在第二按钮右边

for (i=y+1i<=j i++ ){ //判断第二按钮左侧直到第一按钮中间有没有按钮

if (grid[x][i]!=0){

k=0

break

}

else { k=1}

}

if (k==1){

linePassOne()

}

}

if (y==j ) {

linePassOne()

}

}

if (k==2) {

if (x0==x) {

remove()

}

if (x0<x) {

for (n=x0n<=x-1n++ ) {

if (grid[n][j]!=0) {

k=0

break

}

if(grid[n][j]==0 &&n==x-1) {

remove()

}

}

}

if (x0>x) {

for (n=x0n>=x+1 n-- ) {

if (grid[n][j]!=0) {

k=0

break

}

if(grid[n][j]==0 &&n==x+1) {

remove()

}

}

}

}

}

for (i=0i<8i++ ) { //列

if (grid[i][y0]==0) {

if (x>i) {

for (j=x-1j>=i j-- ) {

if (grid[j][y]!=0) {

k=0

break

}

else { k=1}

}

if (k==1) {

rowPassOne()

}

}

if (x<i) {

for (j=x+1j<=ij++ ) {

if (grid[j][y]!=0) {

k=0

break

}

else { k=1}

}

if (k==1) {

rowPassOne()

}

}

if (x==i) {

rowPassOne()

}

}

if (k==2){

if (y0==y) {

remove()

}

if (y0<y) {

for (n=y0n<=y-1 n++ ) {

if (grid[i][n]!=0) {

k=0

break

}

if(grid[i][n]==0 &&n==y-1) {

remove()

}

}

}

if (y0>y) {

for (n=y0n>=y+1 n--) {

if (grid[i][n]!=0) {

k=0

break

}

if(grid[i][n]==0 &&n==y+1) {

remove()

}

}

}

}

}

}

}

public void linePassOne(){

if (y0>j){ //第一按钮同行空按钮在左边

for (i=y0-1i>=j i-- ){ //判断第一按钮同左侧空按钮之间有没按钮

if (grid[x0][i]!=0) {

k=0

break

}

else { k=2} //K=2说明通过了第二次验证

}

}

if (y0<j){ //第一按钮同行空按钮在与第二按钮之间

for (i=y0+1i<=j i++){

if (grid[x0][i]!=0) {

k=0

break

}

else{ k=2}

}

}

}

public void rowPassOne(){

if (x0>i) {

for (j=x0-1j>=i j-- ) {

if (grid[j][y0]!=0) {

k=0

break

}

else { k=2}

}

}

if (x0<i) {

for (j=x0+1j<=i j++ ) {

if (grid[j][y0]!=0) {

k=0

break

}

else { k=2}

}

}

}

public void remove(){

firstButton.setVisible(false)

secondButton.setVisible(false)

fraction()

pressInformation=false

k=0

grid[x0][y0]=0

grid[x][y]=0

}

public void actionPerformed(ActionEvent e) {

if(e.getSource()==newlyButton){

int grid[][] = new int[8][7]

this.grid = grid

randomBuild()

mainFrame.setVisible(false)

pressInformation=false

init()

}

if(e.getSource()==exitButton)

System.exit(0)

if(e.getSource()==resetButton)

reload()

for(int cols = 0cols <6cols++){

for(int rows = 0rows <5rows++ ){

if(e.getSource()==diamondsButton[cols][rows])

estimateEven(cols+1,rows+1,diamondsButton[cols][rows])

}

}

}

public static void main(String[] args) {

lianliankan llk = new lianliankan()

llk.randomBuild()

llk.init()

}

}

//old 998 lines

//new 318 lines

参考资料:http://zhidao.baidu.com/question/36439800.html?fr=qrl3

货不多说直接代码

public class car {

private String car_number

private float car_price

private float rebate//折扣

public float getRebate() {

return rebate

}

public void setRebate(float rebate) {

this.rebate = rebate

}

public String getCar_number() {

return car_number

}

public void setCar_number(String car_number) {

this.car_number = car_number

}

public float getCar_price() {

return car_price

}

public void setCar_price(float car_price) {

this.car_price = car_price

}

//设置价格参数

public void carString() {

car_price=1

car_number="100"

rebate=1

}

//修改价格

public void modify(float price){

car car=new car()

car.setRebate(price)

}

public static void main(String agrs[]) {

car car =new car()

car.carString()//设置参数

System.out.println(car.getRebate())

car.modify((float)0.8)//修改

System.out.println(car.getRebate())

}

}

你好,按照你的要求代码如下,可以直接运行

import java.io.BufferedReader

import java.io.IOException

import java.io.InputStreamReader

public class test {

public static void main(String[] args) {

int count = 0

BufferedReader in = new BufferedReader(new InputStreamReader(System.in))

for (int i = 0i <10i++) {

int a = (int) (Math.random() * 100)

int b = (int) (Math.random() * 100)

int c = (int) (Math.random() * 2)

int r = 0

switch (c) {

case 0:

if (a + b >= 100) {

a = 100 - b

}

System.out.print(a + " + " + b + " = ")

r = a + b

break

case 1:

if (a <b) {

int t = a

a = b

b = t

}

System.out.print(a + " - " + b + " = ")

r = a - b

}

int input

try {

input = Integer.valueOf(in.readLine())

} catch (Exception e1) {

System.out.println("答案错误\n")

continue

}

if (input == r) {

count++

System.out.println("答案正确\n")

} else {

System.out.println("答案错误\n")

}

}

if (null != in) {

try {

in.close()

} catch (IOException e) {

e.printStackTrace()

}

}

System.out.println("答对数量:" + count + "\n得分: " + count * 10)

}

}


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原文地址: http://outofmemory.cn/yw/8045623.html

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