如何用STC产生100K-200K的PWM脉冲，好像进出中断就要了4个机器周期，主要用控制2相步进电机的

首先步进电机一般2KHz正常运转并且平稳，

其次这个“TH0 = 0x0FFTL0 = 0x0FF”存在问题，应该是TH0 = 0x0FTL0 = 0x0F或TH0 = 0xFFTL0 = 0xFF，但这两种都不会是33KHz左右的频率

#include<reg52.h>

#define uchar unsigned signed

sbit jia_key=P3^6

sbit jian_key=P3^7

sbit zf_key=P3^5

bit flag=0

uchar codetable[]={0x01,0x02,0x04,0x08,0x08,0x04,0x02,0x01}

uchar num,qidong,PWM,table_begin

void delay(uchar 1)

{

uchar j,k

for(j=ij>0j--)

for(k=125k>0k--)

}

void key()

{

if(jia_key==0)

{

delay(5)

if(jia_key==0)

{

num++

if(num==4)num=3

while(jia_key==0)

}

}

if(jian_key==0)

{

delay(5)

if(jian_key==0)

if(num!=0)

num--

else

num=0

while(jian_key==0)

}

}

if(zf_key==0)

{

delay(5)

if(zf_key==0)

{

flag=-flag

while(zf_key==0)

}

}

}

void qidong()

{

uchar i,j

switch(num)

{

case 0:PWM=5break

case 1:PWM=4break

case 2:PWM=3break

case 3:PWM=2break

}

if(flag==0)

table_begin=0

else

table_begin=4

for(i=table_begini<4+table_begini++)

{

P1=table[i]

for(j=0j<PWMj++)

delay(10)

}

}

void main()

{

while(1)

{

key()

qidong()

}

}

#include<stc.h>

#define uchr unsigned char

#define uint unsigned int

sbit zh0 = P2^0

sbit zh1 = P2^1//定义两个端口

uint t //变量T

void main()

{

TMOD = 0x01

THO = (65536-50000)/256

TL0 = (65536-50000)%256

EA = 1

ET0 = 1

TR0 =1 //启动中断

while(1)

{

zh0=1

zh1=0 //程序近来后开始正传

if(t==200) //当中断进入200次，也就是10后电机反转，20次是一秒

{

t=0//把T清零

zh0=0

zh1=1

}

}

}

/*中断程序*/

void timer0 () interrupt 1

{

TH0 = (65536-50000)/256

TL0 = (65536-50000)%256

t++

}

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