c语言编写DNA转录程序

A<->T,C<->G

进行互换就可以了

#include<stdio.h>

#include<stdlib.h>

main()

{

char input[50]/*Defined to store the DNA code sequence*/

int i/*Used as counter*/

printf("\n\tInput the DNA sequence you want to convert\n\t")

gets(input)

for(i=0input[i]!='\0'i++)

{

switch(input[i])

{

case 'A':printf("T")break

case 'T':printf("A")break

case 'C':printf("G")break

case 'G':printf("C")break

default:

{

printf("An Unknown match occurs,Fail to respond")

exit(0)/*Quit the program directly*/

}

}

}

system("pause")/*As this program is made in Dev,use this expression to pause the program*/

}

没用C写，用python写的，道理都一样。

def generate(n):  //n为长度

    for i in range(4**n):

        a=[0 for i in range(n)] //a为长度为n的一个序列

        num = i

        z = 0

        while(num!=0):

            a[z]=num%4

            z = z+1

            num = int(num/4)

        for j in a:

            if j==0:

                print('A',end="")

            elif j==1:

                print('T',end="")

            elif j==2:

                print('G',end="")

            else:

                print('C',end="")

        print()

原理就是四进制转换。

当调用函数generate(2)，产生结果AA，TA，GA，CA，AT，TT，GT，CT，AG，TG，GG，CG，AC，TC，GC，CC

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