2道C语言题目

#define N 10

void invert(int *s,int i,int j)

{ int t

if(i<j)

{

t=*(s+i)

*(s+i)=*(s+j)

*(s+j)=t

invert(s,i+1,j-1)

}

}

void main()

{ int a[N],i

for(i=0i<Ni++)

scanf("%d",&*(a+i))

invert(a,0,N-1)

for(i=0i<Ni++)

printf("%d ",a[i])

printf("\n")

}

///////////////////////////////////

#include <stdio.h>

#include <string.h>

#define N 80

int fun( char *s)

{

int count=0, i=0

int flag = 0

while(s[i] != '\0') {

if(flag==0 &&s[i]>举野简='a' &&s[i]<='z') {

count ++flag = 1

}

else if (flag ==1 &&s[i] ==' ')

{

flag = 0

}

i++

}

return count

}

void main()

{ char line[N]

int num=0

printf("正裤Enter a string :\n")

gets(line)

num=fun(line)

printf("The number of word is : %d\n\n",num)

//脊基NONO()

}

#include "薯颂stdio.h"

void find(int *a,int n,int *max,int *min)

{

int i

*max=*min=0

for(i=1i<ni++)

if(a[i]>a[*max])

*max=i

else if(a[i]<a[*min])

*min=i

}

void main( )

{

int a[]={5,8,7,6,2,7,3},max,min

find(a,7,&max,&min)

printf("\n%d, %d\n",max,min)

}

2

#include "洞首stdio.h"

void invert(int *s,int i,int j)

{

int t

if(i<j)

{

t=*(s+i)

*(s+i)=*(s+j)

*(s+j)=t

invert(s,i+1,j-1)

}

}

void main( )

{

int a[10],i

for(i=0i<10i++) scanf("%d",&a[i])

invert(a,0,10-1)

for(i=0i<10i++)

printf("纳手数%d",a[i])

printf("\n")

}