C语言的按键开关防抖程序~

key为按键，规定按下为低电平

if（key==0）

{

delay（50）； //延时50ms，消抖

if（key==0） //再判断是否按下

{

while（！key）； 松手检测

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该按键按郑巧下要实现的功简消能程序

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}

}

我的习惯是拦丛知这样写

使用这个到板子里面：

#include <reg52.h>

sbit ADDR0 = P1^0

sbit ADDR1 = P1^1

sbit ADDR2 = P1^2

sbit ADDR3 = P1^3

sbit ENLED = P1^4

sbit KEY1 = P2^4

sbit KEY2 = P2^5

sbit KEY3 = P2^6

sbit KEY4 = P2^7

unsigned char code LedChar[] = { //数码管显示字符转换表0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E}

void delay()

void main(){

bit keybuf = 1//按键值暂存，临时保存按键的扫描值

bit backup = 1//按键值备份，保存配尘前一次的扫描值

unsigned char cnt = 0//按键计数，记录按键按下的次数

ENLED = 0 //选择数码管 DS1 进行显示

ADDR3 = 1

ADDR2 = 0

ADDR1 = 0

ADDR0 = 0

P2 = 0xF7 //P2.3 置 0，即 KeyOut1 输出低电平

P0 = LedChar[cnt] //显示按键次数初值

while (1){

keybuf = KEY4 //把当前扫描值暂存

if (keybuf != backup){  //当前值与前次值不相等说明此时按键有动作

delay() //延时大约 10ms

if (keybuf == KEY4){  //判断扫描值有没有发生改变，即按键抖动

if (backup == 0){  //如果前次察卖神值为 0，则说明当前是d起动作

cnt++ //按键次数+1

//只用 1 个数码管显示，所以加到 10 就清零重新开始

if (cnt >= 10){

cnt = 0

}

P0 = LedChar[cnt]//计数值显示到数码管上

}

backup = keybuf//更新备份为当败亏前值，以备进行下次比较

}

}

}

}

/* 软件延时函数，延时约 10ms */

void delay(){

unsigned int i = 1000

while (i--)

}

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