// C
#include <stdio.h>
int strnmerge(char*str,int n,char const*s1,char const*s2){
while(n > 0) {
if(!(*s1) && !(*s2)) break
if(*s1 && n > 0) {
*str++ = *s1++
--n
}
if(*s2 && n > 0) {
*str++ = *s2++
--n
}
}
*str = '\0'
}
int main() {
char s1[] 悔早= "aaaa"
char s2[] = "bbbbbbbbb"
char str[100]
strnmerge(str, 10, s1, s2)
printf("s1 = %s\n", s1)
printf("s2 = %s\n", s2)
printf("str = %s\n", str)
return 0
}
// C++
#include <iostream>
using namespace std
int strnmerge(char*str,int 腔汪n,char const*s1,char const*s2){
while(n > 0) {
if(!(*s1) && !(*s2)) break
if(*s1 && n > 0) {
*str++ = *s1++
--n
}
if(*s2 && n > 0) {
*str++ = *s2++
--n
}
}
*str = '\0'
}
int main() {
char s1[] = "aaaa"
char s2[] = "bbbbbbbbb"
char str[100]
strnmerge(str, 10, s1, s2)
cout << "s1 = " 伍前仔<< s1 << endl
cout << "s2 = " << s2 << endl
cout << "str = " << str << endl
return 0
}
#include <iostream>
using namespace std
int _tmain(int argc, _TCHAR* argv[])
{
int a
cout<<"请输入数字凳颤"<<endl
cin>>a
int b=0
while(a)
{
b=a%10+10*b
a=a/10
}
cout<<州销b<<endl
system("pause"册粗游)
return 0
}
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