Java生产者消费者之信号灯法

Java生产者消费者之信号灯法,第1张

Java生产者消费者之信号灯法 Java生产者消费者之信号灯法
package Thread;

//测试生产者消费者问题:信号灯法,标志位解决
public class TestPC2 {
    public static void main(String[] args) {
        TV tv = new TV();
        Player player = new Player(tv);
        Watcher watcher = new Watcher(tv);

        player.start();
        watcher.start();
    }

}

//生产者——>演员
class Player extends Thread{
    TV tv;
    public Player(TV tv){
        this.tv = tv;
    }

    @Override
    public void run() {
        for (int i = 0; i < 20; i++) {
            if (i%2==0){
                this.tv.play("快乐大本营");
            }else {
                this.tv.play("抖音美好生活");
            }
        }
    }
}

//消费者——>观众
class Watcher extends Thread{
    TV tv;
    public Watcher(TV tv){
        this.tv = tv;
    }

    @Override
    public void run() {
        for (int i = 0; i < 20; i++) {
            this.tv.watch();
        }
    }
}

//产品——>节目
class TV{
    //演员表演,观众等待
    //观众观看,演员等待
    String voice;//表演的节目
    boolean flag = true;

    //表演
    public synchronized void play(String voice){
        if (!flag){
            try {
                this.wait();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
        System.out.println("观众表演了"+voice);
        //通知观众观看
        this.notifyAll();//通知唤醒
        this.voice = voice;
        flag = !this.flag;
    }

    //观看
    public synchronized void watch(){
        if (flag){
            try {
                this.wait();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
        System.out.println("观众观看了"+voice);
        this.notifyAll();
        this.flag = !this.flag;
    }
}

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原文地址: http://outofmemory.cn/zaji/4874051.html

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