在Javascript中调用PHP函数

不能以上面说明的方式调用PHP函数。但是，您可以使用AJAX调用PHP脚本，代码如下所示。您也可以在这里找到一个简单的示例。让我知道您是否需要进一步澄清

使用jQuery

<script type="text/javascript" src="./jquery-1.4.2.js"></script><script type="text/javascript">function compute() {    var params="session=123";    $.post('myphpscript.php',params,function(data){  alert(data);//for testing if data is being fetched var myObject = eval('(' + data + ')'); document.getElementById("result").value=myObject(addend_1,addend_2);        }); }</script>

准系统Javascript替代

   <script type="text/javascript">    function compute() {        var params="session=123"        var xmlHttp;         var addend_1=document.getElementById("par_1").value;        var addend_2=document.getElementById("par_2").value;        try         {  xmlHttp = new XMLHttpRequest();         }         catch (e)         {  try  {      xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");  }  catch (e)  {      try      {          xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");      }      catch (e)      {          alert("No Ajax for YOU!");          return false;      }  }         }         xmlHttp.onreadystatechange = function()         {  if (xmlHttp.readyState == 4) {      ret_value=xmlHttp.responseText;     var myObject = eval('(' + ret_value + ')');     document.getElementById("result").value=myObject(addend_1,addend_2); }        }    xmlHttp.open("POST", "http://yoururl/getjs.php", true);        xmlHttp.setRequestHeader("Content-type", "application/x-www-form-urlenpred");        xmlHttp.setRequestHeader("Content-length", params.length);        xmlHttp.setRequestHeader("Connection", "close");        xmlHttp.send(params);    }    </script>