如何使用PHP从MySQL数据库存储和检索图像？

首先，您创建一个MySQL表来存储图像，例如：

create table testblob (    image_id        tinyint(3)  not null default '0',    image_type      varchar(25) not null default '',    imageblob        not null,    image_size      varchar(25) not null default '',    image_ctgy      varchar(25) not null default '',    image_name      varchar(50) not null default '');

然后，您可以将图像写入数据库，如下所示：

 $imgData = file_get_contents($filename);$size = getimagesize($filename);mysql_connect("localhost", "$username", "$password");mysql_select_db ("$dbname");// mysqli // $link = mysqli_connect("localhost", $username, $password,$dbname); $sql = sprintf("INSERT INTO testblob    (image_type, image, image_size, image_name)    VALUES    ('%s', '%s', '%d', '%s')",        mysql_real_escape_string($size['mime']),    mysql_real_escape_string($imgData),    $size[3],    mysql_real_escape_string($_FILES['userfile']['name'])    );mysql_query($sql);

您可以使用以下方法在网页中显示数据库中的图像：

$link = mysql_connect("localhost", "username", "password");mysql_select_db("testblob");$sql = "SELECT image FROM testblob WHERe image_id=0";$result = mysql_query("$sql");header("Content-type: image/jpeg");echo mysql_result($result, 0);mysql_close($link);