poj 1143 Number Game

#include <stdio.h>#include <string.h>#include <algorithm>#include <iostream>#define MAX(a,b) (a) > (b)? (a):(b)#define MIN(a,b) (a) < (b)? (a):(b)#define mem(a) memset(a,0,sizeof(a))#define INF 1000000007#define MAXN 1<<20#define MACN 20#define JUDGE (((1<<(ma[j]-ma[i]-1)) & ~st) &&(ma[j]-ma[i] != 1)) || (!((ma[j]+1)%(ma[i]+1)))using namespace std;int DP[MAXN],ma[MACN],vis[MAXN];int N;int  search(int k,int state){    if(vis[state])return DP[state];    vis[state]=1;    if(state == 0)return 0;    if(k == 1)return DP[state] = 1;//集合里面只有一个数了，一定是必胜状态    int i, j, key=0;    for(i = 0;i < N;i ++ )    {        int st = state;        if((1<<ma[i]) & state)        { for(j = i+1; j < N; j ++ )//首先去掉ma[i]的倍数和（ma[j]-ma[i]）已经使用了的ma[j] {     if( ((1<<ma[j]) & st) && (JUDGE) )     {         st ^= (1<<ma[j]);     } } key = search(k-1, st^(1<<ma[i])); if( !key )return DP[state]=1;//一旦下一个状态有必输的状态，那这个状态就是必胜的        }    }    return DP[state]=0;}int main(){    int cas=1;    while(~scanf("%d",&N) && N)    {        mem(vis);        int i,j,state=0;        int ans[MACN]={0},count=0;        for(i=0;i<N;i++)        { scanf("%d",&ma[i]); ma[i]--; state ^= (1<<ma[i]);//初始化状态集合state        }        sort(ma,ma+N);        for(i = 0; i < N; i ++ )        { int st = state; for(j = i+1; j < N; j ++ ) {     if(JUDGE) st ^= (1<<ma[j]); } if(search(N-1, (1<<ma[i])^st) == 0) {     ans[count++] = ma[i]+1; }        }        printf("Test Case #%dn", cas++);        if(!count)printf("There's no winning move.nn");        else { printf("The winning moves are:"); for(i=0;i<count;i++)     printf(" %d", ans[i]); printf("nn");        }    }    return 0;}