使用每个文件的不同格式序列化同一类中的多个DateTime属性

使用每个文件的不同格式序列化同一类中的多个DateTime属性

NewtonSoft.Json

具有难以理解的结构，您可以使用以下自定义转换器之类的工具来执行所需的 *** 作：

[TestMethod]public void Conversion(){    var obj = new DualDate()    {        DateOne = new DateTime(2013, 07, 25),        DateTwo = new DateTime(2013, 07, 25)    };    Assert.AreEqual("{"DateOne":"07.25.2013","DateTwo":"2013-07-25T00:00:00"}",         JsonConvert.SerializeObject(obj, Formatting.None, new DualDateJsonConverter()));}class DualDate{    public DateTime DateOne { get; set; }    public DateTime DateTwo { get; set; }}class DualDateJsonConverter : JsonConverter{    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)    {        JObject result = new JObject();        DualDate dd = (DualDate)value;        result.Add("DateOne", JToken.FromObject(dd.DateOne.ToString("MM.dd.yyyy")));        result.Add("DateTwo", JToken.FromObject(dd.DateTwo));        result.WriteTo(writer);    }    // Other JsonConverterMethods    public override bool CanConvert(Type objectType)    {        return objectType == typeof(DualDate);    }    public override bool CanWrite    {        get        { return true;        }    }    public override bool CanRead    {        get        { return false;        }    }    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)    {        throw new NotImplementedException();    }}