Symfony2：以多对一形式防止数据库重复

Symfony2：以多对一形式防止数据库重复

代替

if($responsible1){     $entity->setResponsible1($responsible1->getId()); }if($responsible2){     $entity->setResponsible2($responsible2->getId()); }$entity->getResponsible1()->setUsername($entity->getResponsible1()->getNid());$entity->getResponsible2()->setUsername($entity->getResponsible2()->getNid());$entity->getResponsible1()->setPassword($entity->getResponsible1()->getNid());$entity->getResponsible2()->setPassword($entity->getResponsible2()->getNid());

你可以写

if($responsible1){     $entity->setResponsible1($responsible1); }if($responsible2){     $entity->setResponsible2($responsible2); }

它应该工作。

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但是我认为更好的解决方案是在事件中添加事件侦听器

FormEvents::SUBMIT

。此事件使您可以从表单数据的规范化表示形式更改数据。因此，您需要做的就是这样：

public function onSubmit(FormEvent $event){   $student = $event->getData();   if ($student->getResponsible1()) {        $parentNid = $student->getResponsible1()->getNid();        // here you check the database to see if you have a parent with this nid        // if a parent exists, replace the current submitted parent data with the parent entity existing in your db   }

希望这可以帮助。让我知道是否需要提供更多详细信息。