Swift语言NSClassFromString

Swift语言NSClassFromString

请注意，Swift类现在已命名为名称空间，因此它将是“ AppName.MyViewController”而不是“ MyViewController”

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从XCode6-beta 6/7开始不推荐使用

使用XCode6-beta 3开发的解决方案

多亏了Edwin Vermeer的回答，我能够通过执行以下 *** 作来构建一些东西来将Swift类实例化为Obj-C类：

// swift file// extend the NSObject classextension NSObject {    // create a static method to get a swift class for a string name    class func swiftClassFromString(className: String) -> AnyClass! {        // get the project name        if  var appName: String? = NSBundle.mainBundle().objectForInfoDictionaryKey("CFBundleName") as String? { // generate the full name of your class (take a look into your "YourProject-swift.h" file) let classStringName = "_TtC(appName!.utf16count)(appName)(countElements(className))(className)" // return the class! return NSClassFromString(classStringName)        }        return nil;    }}// obj-c file#import "YourProject-Swift.h"- (void)aMethod {    Class class = NSClassFromString(key);    if (!class)        class = [NSObject swiftClassFromString:(key)];    // do something with the class}

编辑

您也可以在纯obj-c中执行此 *** 作：

- (Class)swiftClassFromString:(NSString *)className {    NSString *appName = [[NSBundle mainBundle] objectForInfoDictionaryKey:@"CFBundleName"];    NSString *classStringName = [NSString stringWithFormat:@"_TtC%d%@%d%@", appName.length, appName, className.length, className];    return NSClassFromString(classStringName);}

我希望这会对某人有所帮助！