在C＃中遍历JSON对象

dynamic dynJson = JsonConvert.DeserializeObject(json);foreach (var item in dynJson){    Console.WriteLine("{0} {1} {2} {3}n", item.id, item.displayName,         item.slug, item.imageUrl);}

要么

var list = JsonConvert.DeserializeObject<List<MyItem>>(json);public class MyItem{    public string id;    public string displayName;    public string name;    public string slug;    public string imageUrl;}