Java ProcessBuilder：转发已启动进程的stdout和stderr，而不会阻塞主线程

Java ProcessBuilder：转发已启动进程的stdout和stderr，而不会阻塞主线程

在Java 6或更早版本中，唯一的办法是使用所谓的

StreamGobbler

（开始创建）：

StreamGobbler errorGobbler = new StreamGobbler(p.getErrorStream(), "ERROR");// any output?StreamGobbler outputGobbler = new StreamGobbler(p.getInputStream(), "OUTPUT");// start gobblersoutputGobbler.start();errorGobbler.start();

…

private class StreamGobbler extends Thread {    InputStream is;    String type;    private StreamGobbler(InputStream is, String type) {        this.is = is;        this.type = type;    }    @Override    public void run() {        try { InputStreamReader isr = new InputStreamReader(is); BufferedReader br = new BufferedReader(isr); String line = null; while ((line = br.readLine()) != null)     System.out.println(type + "> " + line);        }        catch (IOException ioe) { ioe.printStackTrace();        }    }}

对于Java 7，请参阅Evgeniy Dorofeev的答案。