int上的基本算术运算-Java

int上的基本算术运算-Java

上的 *** 作

byte

，

char

并且

short

被加宽到

int

除非编译器可以确定该值的范围。

final byte a = 3, b = 4;byte c = a * b; // compilesfinal byte a = 3, b = 40;byte c = a * b; // compilesfinal int a = 3, b = 4;byte c = a * b; // compiles !!

但

byte a = 3, b = 4;byte c = a * b; // doesn't compile as the result of this will be `int` at runtime.final byte a = 30, b = 40;byte c = a * b; // doesn't compile as the value is too large, will be an `int`

BTW即使发生溢出也会编译。：]

final int a = 300000, b = 400000;int c = a * b; // compiles but overflows, is not made a `long`