用JAXB解组通用列表

感谢Blaise Doughan和他的文章，我找到了解决方案。

首先，我们需要本文提供的Wrapper类：

@XmlRootElementpublic class Wrapper<T> {  private List<T> items;  public Wrapper() {    items = new ArrayList<T>();  }  public Wrapper(List<T> items) {    this.items = items;  }  @XmlAnyElement(lax=true)  public List<T> getItems() {    return items;  }}

然后，我修改了Response类以便使用它：

@XmlRootElement@XmlAccessorType(XmlAccessType.FIELD)public class Response<T> {  @XmlElement  protected String status;  @XmlElement  protected Wrapper<T> result;  ...  public Response(String status, List<T> result) {    this.status = status;    this.result = new Wrapper<>(result);  }  ...  public List<T> getResult() {    return result.getItems();  }  ...}

最后是解组代码：

JAXBContext context = JAXBContext.newInstance(Response.class, Project.class, User.class, Wrapper.class);Unmarshaller unmarshaller = context.createUnmarshaller();StreamSource source = new StreamSource(new File("responseProject.xml"));Response<Project> responseProject = (Response<Project>)unmarshaller.unmarshal(source);System.out.println(responseProject.getStatus());for (Project project:responseProject.getResult()) System.out.println(project);source = new StreamSource(new File("responseUser.xml"));Response<User> responseUser = (Response<User>)unmarshaller.unmarshal(source);System.out.println(responseUser.getStatus());for (User user:responseUser.getResult()) System.out.println(user);

我已经将Wrapper类添加到上下文类列表中。

另外，您可以将此注释添加到Response类：

@XmlSeeAlso({Project.class, User.class})