将文件从动作脚本发送到servlet

将文件从动作脚本发送到servlet

默认情况下，flash无法

multipart

使用参数创建请求，您必须手动构造它。这是我在项目中使用的简单实用程序方法：

private static const BOUNDARY:String = "boundary"; public static function createMultiPartRequest(url:String, bytes:ByteArray, fileProp:String="file1", fileName:String="file1.png", params:Object=null):URLRequest{    var request:URLRequest = new URLRequest(url);    var header1:String = "rn--" + BOUNDARY + "rn" +         "Content-Disposition: form-data; name=""+fileProp+""; filename=""+fileName+""rn" +         "Content-Type: image/pngrn" + "rn";    var headerBytes1:ByteArray = new ByteArray();    headerBytes1.writeMultiByte(header1, "ascii");    var postdata:ByteArray = new ByteArray();    postData.writeBytes(headerBytes1, 0, headerBytes1.length);    if(bytes)        postData.writeBytes(bytes, 0, bytes.length);    if (!params)        params = {};    if (!params.Upload)        params.Upload = "Submit Query";    for (var prop:String in params) {        var header:String = "--" + BOUNDARY + "rn" + "Content-Disposition: form-data; name=""+prop+""rn" + "rn" + params[prop]+"rn" + "--" + BOUNDARY + "--";        var headerBytes:ByteArray = new ByteArray();        headerBytes.writeMultiByte(header, "ascii");        postData.writeBytes(headerBytes, 0, headerBytes.length);    }    request.data = postData;    request.method = URLRequestMethod.POST;    request.contentType = "multipart/form-data; boundary=" + BOUNDARY;    return request;}

因此，您应该以以下方式修改代码：

    var uploadRequest:URLRequest = createMultiPartRequest("http://127.0.0.1:8080/uploading/upservlet", myByteArray, "file1", recorder.output, {param1:value1});    var uploader:URLLoader = new URLLoader;    uploader.addEventListener(ProgressEvent.PROGRESS, onUploadProgress);    uploader.addEventListener(Event.COMPLETE, onUploadComplete);    uploader.dataFormat = URLLoaderDataFormat.BINARY;    uploader.load(uploadRequest);