您如何自定义JAXB如何生成复数方法名称？

默认情况下，为您的架构片段生成以下内容：

    import java.util.ArrayList;    import java.util.List;    import javax.xml.bind.annotation.XmlAccessType;    import javax.xml.bind.annotation.XmlAccessorType;    import javax.xml.bind.annotation.XmlElement;    import javax.xml.bind.annotation.XmlType;    @XmlAccessorType(XmlAccessType.FIELD)    @XmlType(name = "physicianList", propOrder = {        "physician"    })    public class PhysicianList {        @XmlElement(name = "Physician")        protected List<Physician> physician;        public List<Physician> getPhysician() { if (physician == null) {     physician = new ArrayList<Physician>(); } return this.physician;        }    }

如果您注释XML模式：

    <xs:schema        xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"        xmlns:xs="http://www.w3.org/2001/XMLSchema"        jaxb:version="2.1">        <xs:complexType name="physician"> <xs:sequence> </xs:sequence>        </xs:complexType>        <xs:complexType name="physicianList"> <xs:sequence>     <xs:element name="Physician"      type="physician"      minOccurs="0"      maxOccurs="unbounded"><xs:annotation>    <xs:appinfo>        <jaxb:property name="physicians"/>    </xs:appinfo></xs:annotation>      </xs:element> </xs:sequence>        </xs:complexType>    </xs:schema>

然后，您可以生成所需的类：

import java.util.ArrayList;import java.util.List;import javax.xml.bind.annotation.XmlAccessType;import javax.xml.bind.annotation.XmlAccessorType;import javax.xml.bind.annotation.XmlElement;import javax.xml.bind.annotation.XmlType;@XmlAccessorType(XmlAccessType.FIELD)@XmlType(name = "physicianList", propOrder = {    "physicians"})public class PhysicianList {    @XmlElement(name = "Physician")    protected List<Physician> physicians;    public List<Physician> getPhysicians() {        if (physicians == null) { physicians = new ArrayList<Physician>();        }        return this.physicians;    }}