用Java解析高级XML

用Java解析高级XML

//规范化您的XML，然后

document

通过该XML 创建一个，然后遵循以下代码

NodeList nList = doc.getElementsByTagName("foo");        for (int temp = 0; temp < nList.getLength(); temp++) { // loop for foo Node nodeTable = nList.item(temp); Element xmlFoo = (Element) nodeTable; if (nodeTable.getNodeType() == Node.ELEMENT_NODE) { NodeList nodeListFoo1 = xmlFoo.getElementsByTagName("foo1"); for (int i = 0; i < nodeListFoo1.getLength(); i++) { // loop for foo1     Node nodefoo2 = nodeListFoo1.item(i);     Element elementfoo1 = (Element) nodefoo2;     // Collect foo2      NodeList nodeListfoo2Name = elementfoo1.getElementsByTagName("foo2");     for (int j = 0; j < nodeListfoo2Name.getLength(); j++) { //// loop for foo2         Node nodefoo2Name = nodeListfoo2Name.item(j);         Element elementfoo2Name = (Element) nodefoo2Name;         //TODO: write pre here, what you want to collect from foo2         }     } }        }