将嵌套的Python字典转换为对象？

更新：在Python 2.6及更高版本中，请考虑namedtuple数据结构是否满足你的需求：

>>> from collections import namedtuple>>> MyStruct = namedtuple('MyStruct', 'a b d')>>> s = MyStruct(a=1, b={'c': 2}, d=['hi'])>>> sMyStruct(a=1, b={'c': 2}, d=['hi'])>>> s.a1>>> s.b{'c': 2}>>> s.cTraceback (most recent call last):  File "<stdin>", line 1, in <module>AttributeError: 'MyStruct' object has no attribute 'c'>>> s.d['hi']

备选方案（原始答案内容）为：

class Struct:    def __init__(self, **entries):        self.__dict__.update(entries)

然后，你可以使用：

>>> args = {'a': 1, 'b': 2}>>> s = Struct(**args)>>> s<__main__.Struct instance at 0x01D6A738>>>> s.a1>>> s.b2