LeetCode第3题 Longest Substring Without Repeating Character(c++)

LeetCode第3题 Longest Substring Without Repeating Character(c++),第1张

LeetCode第3题 Longest Substring Without Repeating Character(c++)

Given a string s, find the length of the longest substring without repeating characters.

Example 1:

Input: s = "abcabcbb"
Output: 3
Explanation: The answer is "abc", with the length of 3.
Example 2:

Input: s = "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.
Example 3:

Input: s = "pwwkew"
Output: 3
Explanation: The answer is "wke", with the length of 3.
Notice that the answer must be a substring, "pwke" is a subsequence and not a substring.
Example 4:

Input: s = ""
Output: 0
 

Constraints:

0 <= s.length <= 5 * 104
s consists of English letters, digits, symbols and spaces.

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/longest-substring-without-repeating-characters
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

题目大意:

返回无重复字母的最大子串的长度。

实现思路:

利用双指针,并将每个元素存入set中,利用set.count()来查看是否存在重复字母,并进行相应的指针移动。

实现代码:

class Solution {
public:
    int lengthOfLongestSubstring(string s) {
        set st;
        int n=s.length();
        int l=0,r=0;
        int ans=0;
        for(int i=0;i 

欢迎分享,转载请注明来源:内存溢出

原文地址: http://outofmemory.cn/zaji/5634950.html

(0)
打赏 微信扫一扫 微信扫一扫 支付宝扫一扫 支付宝扫一扫
上一篇 2022-12-16
下一篇 2022-12-16

发表评论

登录后才能评论

评论列表(0条)

保存