Python测试字符串是否为一组特定值之一

Python测试字符串是否为一组特定值之一

你忘了写

s == "no"

你的第一本

elif:

def shut_down(s):    if s == "Yes" or s == "yes" or s == "YES":        return "Shutting down..."    elif s == "No" or "no" or "NO":  # you forgot the s== in this line        return "Shutdown aborted!"     else:        return "Sorry, I didn't understand you."

做这个：

def shut_down(s):    if s == "Yes" or s == "yes" or s == "YES":        return "Shutting down..."    elif s == "No" or s == "no" or s == "NO":       # fixed it         return "Shutdown aborted!"    else:        return "Sorry, I didn't understand you."

这是因为：

elif s == "No" or "no" or "NO":  #<---thiselif s == "No" or True or True:  #<---is the same as this

由于这是公认的答案，因此我将详细介绍标准做法：不考虑大小写而比较字符串的约定（equalsIgnoreCase）的用法

.lower()

如下：

elif s.lower() == "no":