在Python中实现回调-将可调用的引用传递给当前函数

在Python中实现回调-将可调用的引用传递给当前函数

任何定义的函数都可以通过简单地使用其名称来传递，而无需

()

在调用末尾添加：

def my_callback_func(event):    # do stuffo = Observable()o.subscribe(my_callback_func)

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其他示例用法：

class CallbackHandler(object):    @staticmethod    def static_handler(event):        # do stuff    def instance_handler(self, event):        # do stuffo = Observable()# static methods are referenced as <class>.<method>o.subscribe(CallbackHandler.static_handler)c = CallbackHandler()# instance methods are <class instance>.<method>o.subscribe(c.instance_handler)# You can even pass lambda functionso.subscribe(lambda event: <<something involving event>>)