反应分页按钮前进和后退python

这是我想出的。

基本上，我们有一个循环，可根据所需反应检查每个反应，然后删除旧消息并发送新消息（如果我们看到了所寻找的反应之一）。

from discord.ext import commandsbot = commands.Bot(command_prefix='!')left = '⏪'right = '⏩'messages = ("1", "2", "3")def predicate(message, l, r):    def check(reaction, user):        if reaction.message.id != message.id or user == bot.user: return False        if l and reaction.emoji == left: return True        if r and reaction.emoji == right: return True        return False    return check@bot.command(pass_context=True)async def series(ctx):    index = 0    while True:        msg = await bot.say(messages[index])        l = index != 0        r = index != len(messages) - 1        if l: await bot.add_reaction(msg, left)         if r: await bot.add_reaction(msg, right)        # bot.wait_for_reaction        react, user = await bot.wait_for_reaction(check=predicate(msg, l, r))        if react.emoji == left: index -= 1        elif react.emoji == right: index += 1        await bot.delete_message(msg)bot.run("TOKEN")

有人要求提供一种用于编辑消息的版本，而不是发送新消息，我也将其更新为最新版本：

@bot.command(pass_context=True)async def series(ctx):    index = 0    msg = None    action = ctx.send    while True:        res = await action(content=messages[index])        if res is not None: msg = res        l = index != 0        r = index != len(messages) - 1        if l: await msg.add_reaction(left)         if r: await msg.add_reaction(right)        react, user = await bot.wait_for('reaction_add', check=predicate(msg, l, r))        if react.emoji == left: index -= 1        elif react.emoji == right: index += 1        action = msg.edit