分组Python元组列表

itertools.groupby

import itertoolsimport operatorL = [('grape', 100), ('grape', 3), ('apple', 15), ('apple', 10),     ('apple', 4), ('banana', 3)]def accumulate(l):    it = itertools.groupby(l, operator.itemgetter(0))    for key, subiter in it:       yield key, sum(item[1] for item in subiter)>>> print list(accumulate(L))[('grape', 103), ('apple', 29), ('banana', 3)]>>>