如何在Python中验证字典的结构（或架构）？

不使用库，您还可以定义一个简单的递归函数，如下所示：

def check_structure(struct, conf):    if isinstance(struct, dict) and isinstance(conf, dict):        # struct is a dict of types or other dicts        return all(k in conf and check_structure(struct[k], conf[k]) for k in struct)    if isinstance(struct, list) and isinstance(conf, list):        # struct is list in the form [type or dict]        return all(check_structure(struct[0], c) for c in conf)    elif isinstance(struct, type):        # struct is the type of conf        return isinstance(conf, struct)    else:        # struct is neither a dict, nor list, not type        return False

假设配置可以包含不在您的结构中的键，如您的示例。

更新：新版本还支持列表，例如

'foo': [{'bar': int}]