为什么matplotlib无法在其他线程中绘图？

为什么matplotlib无法在其他线程中绘图？

正如其他人所说，Matplotlib不是线程安全的，您可以选择的一种方法是使用多处理。您说这对您不利，因为您需要访问来自不同过程的轴，但是您可以通过在模拟过程和根过程之间共享
数据 ，然后在根过程中管理所有与绘图相关的活动来克服这一问题。例如

import matplotlibmatplotlib.use('TkAgg')from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg, NavigationToolbar2TkAggimport multiprocessingimport timeimport randomfrom Tkinter import *#Create a windowwindow=Tk()def main():    #Create a queue to share data between process    q = multiprocessing.Queue()    #Create and start the simulation process    simulate=multiprocessing.Process(None,simulation,args=(q,))    simulate.start()    #Create the base plot    plot()    #Call a function to update the plot when there is new data    updateplot(q)    window.mainloop()    print 'Done'def plot():    #Function to create the base plot, make sure to make global the lines, axes, canvas and any part that you would want to update later    global line,ax,canvas    fig = matplotlib.figure.Figure()    ax = fig.add_subplot(1,1,1)    canvas = FigureCanvasTkAgg(fig, master=window)    canvas.show()    canvas.get_tk_widget().pack(side=TOP, fill=BOTH, expand=1)    canvas._tkcanvas.pack(side=TOP, fill=BOTH, expand=1)    line, = ax.plot([1,2,3], [1,2,10])def updateplot(q):    try:       #Try to check if there is data in the queue        result=q.get_nowait()        if result !='Q':  print result      #here get crazy with the plotting, you have access to all the global variables that you defined in the plot function, and have the data that the simulation sent.  line.set_ydata([1,result,10])  ax.draw_artist(line)  canvas.draw()  window.after(500,updateplot,q)        else:  print 'done'    except:        print "empty"        window.after(500,updateplot,q)def simulation(q):    iterations = xrange(100)    for i in iterations:        if not i % 10: time.sleep(1)     #here send any data you want to send to the other process, can be any pickable object q.put(random.randint(1,10))    q.put('Q')if __name__ == '__main__':    main()