位掩码的大小有实际限制吗？

位掩码的大小有实际限制吗？

在我脑海中，我写了一个

set_bit

and

get_bit

函数，它可以使用字节数组和数组中的位偏移量，并使用一些位扭曲来设置/获取数组中的适当位。像这样的东西（用C语言编写，但希望您能理解）：

// sets the n-th bit in |bytes|. num_bytes is the number of bytes in the array// result is 0 on success, non-zero on failure (offset out-of-bounds)int set_bit(char* bytes, unsigned long num_bytes, unsigned long offset){  // make sure offset is valid  if(offset < 0 || offset > (num_bytes<<3)-1) { return -1; }  //set the right bit  bytes[offset >> 3] |= (1 << (offset & 0x7));  return 0; //success }//gets the n-th bit in |bytes|. num_bytes is the number of bytes in the array// returns (-1) on error, 0 if bit is "off", positive number if "on"int get_bit(char* bytes, unsigned long num_bytes, unsigned long offset){  // make sure offset is valid  if(offset < 0 || offset > (num_bytes<<3)-1) { return -1; }  //get the right bit  return (bytes[offset >> 3] & (1 << (offset & 0x7));}