http://noi.openjudge.cn/ch0105/08/
#include#include int main() { int n,sum,x,i; scanf("%d",&n); sum=(n-2)*180; for(i=1;i<=n-1;i++) { scanf("%d",&x); sum-=x; } printf("%dn",sum); return 0; }
1.7 编程基础之字符串 python版.rar
https://download.csdn.net/download/dllglvzhenfeng/47521041
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