Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where . The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
不完备的题解:
#include#include #include #include #include using namespace std; #define MAX 0x3FFFFFFF typedef long long ll; int main() { ll a, b, c, c_tem; cin >> a >> b; c = a + b, c_tem = abs(c); if (c == 0) { cout << 0; return 0; } vector res; int sign = c / abs(c); while (c_tem != 0) { int tem = c_tem % 10; res.push_back(tem); c_tem = c_tem / 10; } if (sign == -1) cout << "-"; int times = 0; while (res.size() != 0) { cout << res.back(); res.pop_back(); times++; if (times % 3 == 0&& res.size() != 0) cout << ','; } return 0; }
思路不难理解:先求得两数和,再求符号,拆成每个位并入栈,再d栈,顺便打印逗号就行了。
测试了很多组数据,也考虑了结果为0的情况,不过不知道为什么只有部分正确
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