使用 Stream的sort() 方法,并结合 Comparator 类 进行排序,主要解决以下两个问题:
一、当某个字段为空时,怎么进行排序?—使用 Comparator.nullsFirst() 或者 Comparator.nullsLast( ) 进行非空的剔除
List list = collect.stream().filter(StreamUtil.distinctByKey(AdminCertificateVo::getAdminId)).distinct() .sorted(Comparator.comparing(AdminCertificateVo::getIssueDate,Comparator.nullsFirst(String::compareTo)).reversed()) .sorted(Comparator.comparing(AdminCertificateVo::getState,Comparator.nullsFirst(Integer::compareTo)).reversed()) .collect(Collectors.toList());
这段代码中,按照issueDate和state降序,如果为null则排在结尾。
二、如果比较两个字段?—使用 thenComparing( )
Listcollect4 = userList.stream().sorted(Comparator.comparing(User::getAddress, Comparator.nullsFirst(String::compareTo)). thenComparing(User::getPhone, Comparator.nullsFirst(String::compareTo)).reversed()).collect(Collectors.toList()); System.out.println("先根据地址正序排序,再根据电话逆序排序,null的在后面: "); System.out.println(JSON.toJSONString(collect4)); System.out.println("========================="); System.out.println();
运行结果:
先根据地址正序排序,再根据电话逆序排序,null的在后面: [{"address":"NY","age":28,"userName":"Durant"},{"address":"Miami","age":29,"phone":"55555","userName":"Wade"},{"address":"LA","age":36,"phone":"11111","userName":"Bryant"},{"address":"Houston","age":39,"phone":"33333","userName":"Harden"},{"age":37,"phone":"22222","userName":"James"}] =========================
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