php查询mysql的数值结果怎么相加？

select sum("金额字段") as cmoney from 表 where 1\x0d\x0a\x0d\x0a然后你输出cmoney这个就是相加的效果。\x0d\x0a还有一种比较差点的方法就是：\x0d\x0a 1、select 金额字段 from 表 where 1\x0d\x0a2、获取你得到的所有信息，然后foreach 把所有的金额相加就行，\x0d\x0a 实例：$sql = "select money from cg_money where 1"\x0d\x0a$query = mysql_query($sql)\x0d\x0a$m = 0\x0d\x0a\x0d\x0awhile($rs = mysql_fetch_array($sql)){\x0d\x0a $m = $m+$rs['money']\x0d\x0a\x0d\x0a}\x0d\x0aecho $m这个也是可以获取所有的money的，就是费事了点，还是上面的呢个方法好滴，也就是楼上的呢个方法

function sumShuzi(&$tree, &$updateData = array()) {

  $sum = 0

  // foreach($tree as $key => $item) {  //这句话有毒

  foreach($tree as $key => &$item) {

    if(isset($item['children'])) {

      $oldPshuzi = $tree[$key]['Pshuzi']

      $tree[$key]['Pshuzi'] = sumShuzi($item['children'], $updateData)

      if($oldPshuzi != $tree[$key]['Pshuzi']) {

        $updateData[$item['id']] = array($tree[$key]['Pshuzi'], $tree[$key]['Pname_ch'])

      }

    }

    $sum += $tree[$key]['Pshuzi']

  }

  return $sum

}

$tree = json_decode('[{"id":"1","Pid":"0","Pname_ch":"\u6e20\u9053\u90e8","Pshuzi":"1638000","children":[{"id":"4","Pid":"1","Pname_ch":"\u9500\u552e\u4e8c\u90e8","Pshuzi":"895000","children":[{"id":"13","Pid":"4","Pname_ch":"\u5468\u7ecf\u7406","Pshuzi":"28","children":[{"id":"28","Pid":"13","Pname_ch":"\u6e56\u5357","Pshuzi":"158000"},{"id":"35","Pid":"13","Pname_ch":"\u65b0\u7586","Pshuzi":"19000"}]},{"id":"40","Pid":"4","Pname_ch":"\u9648\u7ecf\u7406","Pshuzi":"5000"}]}]}]', true)

//$tree是具有父子关系的数据树

sumShuzi($tree, $updateData)

foreach ($updateData as $id => $item) {

  $sql = "update your_table set Pshuzi={$item[0]} where id={$id}"

  mysqli_query($db, $sql)    //$db是你的数据库连接结果

}

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