mysql 查询结果求和

1、创建三张测试表，

create table pw_memberinfo(uid int, name varchar(20))

create table pw_members(companyid int, uid int)

create table pw_memberdata(uid int, deposit int, ddeposit int, money int)

2、三张表，分别插入测试数据，

insert into pw_members values(1, 1)

insert into pw_members values(1, 2)

insert into pw_members values(1, 3)

insert into pw_memberinfo values(1, 'name_1')

insert into pw_memberinfo values(2, 'name_2')

insert into pw_memberinfo values(3, 'name_3')

insert into pw_memberdata values(1,30,50,150)

insert into pw_memberdata values(2,77,50,12)

insert into pw_memberdata values(3,44,50,82)

3、查看pw_memberdata表中的记录，select * from pw_memberdata t，

4、编写sql语句，

select * from (SELECT i.uid, sum(deposit+ddeposit+money) as allmoney

FROM pw_memberinfo i

LEFT JOIN pw_members m ON m.uid=i.uid

LEFT JOIN pw_memberdata d ON i.uid=d.uid

group by i.uid

) t where allmoney>200

SELECT i.uid,sum(deposit+ddeposit+money) as allmoney FROM

另外,因为你是多个表的左联接,考虑到有NULL记录的存在,建议你用函数ifnull处理下,避免由于NULL而造成结果有误,最终改成这样:

SELECT i.uid,sum(ifnull(deposit,0)+ifnull(ddeposit,0)+ifnull(money,0)) as allmoney

FROM pw_memberinfo i LEFT JOIN pw_members m ON m.uid=i.uid LEFT JOIN pw_memberdata d ON i.uid=d.uid

where ifnull(deposit,0)+ifnull(ddeposit,0)+ifnull(money,0)>2000

MSSQL里：

select t_no,sum_value=sum(t_value) from t

group by t_no

order by sum_value desc

已知表一，用什么语句能把数据写入表2

分数 FROM 表1 WHERE 考试科目=' AND 表2.姓名数学'.姓名 = 表1语文',数学)

SELECT 姓名

INSERT INTO 表2(语文)

SELECT 分数 FROM 表1 WHERE 考试科目='INSERT INTO 表2(姓名

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