本人想做一个51单片机的LED点阵显示,怎么从单片机调用所有汉字

本人想做一个51单片机的LED点阵显示,怎么从单片机调用所有汉字,第1张

1、选一个带汉字库的LED,直接写汉字内码就可以显示汉字了,应该最方便。

2、将国标汉字库转换成LED的汉子库,转换软件可以从供应商求取,也可以自己编一个小程序自己生成。从网上找也可以,很多很多。

#include"at89x51h"

unsigned char code led[]={0x10,0x04,0x10,0x03,0xD0,

0x00,0xFF,0xFF,0x90,0x00,

0x18,0x1D,0xF7,0x13,0x14,

0x11,0x54,0x15,0x94,0x19,

0x14,0x51,0x14,0x91,0xF6,

0x7F,0x04,0x11,0x00,0x01,

0x00,0x00,

0x04,0x04,0x04,0x02,0x04,

0x01,0xC4,0xFF,0x3F,0x00,

0x04,0x20,0x04,0x10,0x04,

0x08,0xE4,0x3F,0x04,0x42,

0x1F,0x41,0x84,0x40,0xC4,

0x40,0x06,0x40,0x04,0x70,

0x00,0x00};

unsigned char i=0,j=0,time_50ms=0;

delay();

main()

{

TMOD=0X01;

TH0=0X3C;

TL0=0XB0;

TR0=1;

ET0=1;

EA=1;

while(1)

{

P1=i;

P2=led[32j+2i];

P3=led[32j+2i+1];

delay();

i++;

if(i==16)

i=0;

if(time_50ms==20)

{

time_50ms=0;

j++;

if(j==2)

j=0;

}

}

}

int_T0() interrupt 1

{

TH0=0X3C;

TL0=0XB0;

time_50ms++;

}

delay()

{

unsigned char t1;

for(t1=0;t1<100;t1++);

}

你好!!

改了你的程序,还有一个警告,是来自你程序的嵌套了,你在优化一下吧;

代码发给你,主要是修改了fun函数的声明部分:

#include<reg52h>

#define char unsigned char

#define int unsigned int

sbit f0=P1^0;

sbit f1=P1^1;

sbit f2=P1^2;

sbit f3=P1^3;

sbit f4=P1^4;

char key,keytmp();

char code distaba[]=

{0xfd,0xae,0xff,0xae,0xfd,0x06,0xff,0x40,

0xf5,0xb5,0xbf,0xb5,0xf5,0x8a,0x7f,0x2a,

0x20,0xe9,0x8e,0x8e,0xe9,0x22,0x7f,0xa0,

0x10,0x10,0xff,0x10,0x10,0x02,0x7f,0xa0,

0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

};

char code scan_cona [8]=

{0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};//列扫描控制字

void fun();

//按键扫描函数//   

  void keyscan()   

   {          

    if(f0==0)    

      { 

  while(1) 

  {

  fun(); 

  }   

         

 }    }

//1ms延时子程序

void delay1ms(int t)

{

int i,j;

for(i=0;i<t;i++)

for(j=0;j<120;j++);

keyscan();

}

//向右滚动显示

void fun()

{

int m,n,h;

  for(h=0;h<32;h++)//控制显示字数(32/8=4个)

{for(n=0;n<25;n++)//控制帧移动速度

{for(m=0;m<8;m++)//显示1帧扫描(分8行,每行亮1ms)

{P2=scan_cona[7-m];P0=distaba[m+h];delay1ms(1);}

}

}

}

//主程序  

   main()   

    {      

P0=0XFF;

P1=0XFF;

P2=0XFF;

P3=0XFF;

while(1)

  { fun();}

 }

我也不怎么会,还在学习中

下面有一个1616的C程序

参考一下。。。

字模软件你要的话我可以给你

共同学习。。。

#include<reg51h>

sbit P20=P2^0;

sbit P22=P2^2;

unsigned char code text[]={

0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

0x00,0x80,0x00,0x80,0xFC,0x80,0x05,0xFE,0x85,0x04,0x4A,0x48,0x28,0x40,0x10,0x40,

0x18,0x40,0x18,0x60,0x24,0xA0,0x24,0x90,0x41,0x18,0x86,0x0E,0x38,0x04,0x00,0x00,/"欢",0/

0x40,0x00,0x21,0x80,0x36,0x7C,0x24,0x44,0x04,0x44,0x04,0x44,0xE4,0x44,0x24,0x44,

0x25,0x44,0x26,0x54,0x24,0x48,0x20,0x40,0x20,0x40,0x50,0x00,0x8F,0xFE,0x00,0x00,/"迎",1/

0x01,0x00,0x21,0x10,0x19,0x18,0x0D,0x10,0x09,0x20,0x01,0x04,0x7F,0xFE,0x04,0x40,

0x04,0x40,0x04,0x40,0x04,0x40,0x08,0x42,0x08,0x42,0x10,0x42,0x20,0x3E,0x40,0x00,/"光",2/

0x01,0x00,0x09,0x80,0x09,0x00,0x49,0xFE,0x4A,0x20,0x4A,0x10,0x4C,0x10,0x49,0x04,

0x49,0xFE,0x49,0x24,0x49,0x24,0x49,0x24,0x49,0x24,0x09,0xFC,0x09,0x04,0x00,0x00,/"临",3/

0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

};

void Delay(unsigned char i)

{

unsigned char j;

for(;i>0;i--)

for(j=0;j<80;j++)

{;}

}

void main()

{

unsigned int a,e;

unsigned char b,c,d=0;

SCON=0;

while(1)

{

for(e=0;e<160;e=e+32)

{

for(a=0;a<8;a++)

{

for(b=0;b<8;b++)

{

for(c=0;c<32;c++)

{

SBUF=~(text[e+c+32]>>(8-a)|text[e+c+1]<<a);

while(TI==0);

TI=0;

SBUF=~(text[e+c+1]>>(8-a)|text[e+c]<<a);

while(TI==0);

TI=0;

c++;

P20=1;

P1=d;

P22=0;

Delay(3);

P20=0;

P22=1;

d++;

if(d==16)d=0;

}

}

}

for(a=0;a<8;a++)

{

for(b=0;b<8;b++)

{

for(c=0;c<32;c++)

{

SBUF=~(text[e+c+1+32]>>(8-a)|text[e+c+32]<<a);

while(TI==0);

TI=0;

SBUF=~(text[e+c+32]>>(8-a)|text[e+c+1]<<a);

while(TI==0);

TI=0;

c++;

P20=1;

P1=d;

P22=0;

Delay(3);

P20=0;

P22=1;

d++;

if(d==16)d=0;

}

}

}

}

for(a=0;a<160;a=a+2)

{

for(b=0;b<8;b++)

{

for(c=1;c<32;c++)

{

if(a+c<160){

SBUF=~text[a+c];

while(TI==0);

TI=0;

SBUF=~text[a+c-1];

while(TI==0);

TI=0;}

else {

SBUF=~text[a+c-160];

while(TI==0);

TI=0;

SBUF=~text[a+c-1-160];

while(TI==0);

TI=0;}

P1=c/2;

c++;

P20=1;

P22=0;

Delay(3);

P22=1;

P20=0;

}

}

}

}

}

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