python的Ruby String#succ的对应物？

概述我想知道在 python中是否有一个函数(或方法)增加字符串,如 Ruby的 String#succ方法,即： ~ $irb --simple-prompt>> '2'.succ=> "3">> '99'.succ=> "100">> 'zzz'.succ=> "aaaa">> 以下实现是我可以通过ruby的String#succ实现得到的最接近的实现 def succ(s): 我想知道在 python中是否有一个函数(或方法)增加字符串,如 Ruby的 String#succ方法,即：

~ $irb --simple-prompt>> '2'.succ=> "3">> '99'.succ=> "100">> 'zzz'.succ=> "aaaa">>

解决方法 以下实现是我可以通过ruby的String#succ实现得到的最接近的实现

def succ(s):    if not isinstance(s,(str,string)):        raise TypeError("succ works only with strings")    if not s: return    if max(map(ord,s)) > 127:        raise TypeError("succ currently only supports ascii")    #Three different character category honoured    #  1. ascii lowercase Alpha    #  2. ascii uppercase Alpha    #  3. digits    #  4. ascii nonAlpha characters (the entire ascii set)    lower = string.ascii_lowercase + 'a'    upper = string.ascii_uppercase + 'A'    digits = string.digits + '0'    nonAlpha = map(chr,range(0,256)) + [chr(0)]    def incr(ch):        '''        Generates the next character in sequence using the following rules            1. Incrementing a digit always results in another digit            2. Incrementing a letter results in another letter of the same case.            3. Incrementing nonAlphanumerics uses the underlying               character set’s collating sequence.        '''        if ch.isdigit(): return digits[ord(ch) - ord("0") + 1]        if ch.islower(): return lower[ord(ch) - ord('a') + 1]        if ch.isupper(): return upper[ord(ch) - ord('A') + 1]        return nonAlpha[ord(ch) + 1]    def last(ch):        '''        Returns the last character in its catagory        '''        if ch.isdigit(): return digits[-2]        if ch.islower(): return lower[-2]        if ch.isupper(): return upper[-2]        return nonAlpha[-2]    def first(ch):        '''        Returns the last first in its catagory        '''        if ch.isdigit(): return digits[0]        if ch.islower(): return lower[0]        if ch.isupper(): return upper[0]        return nonAlpha[0]    def islast(ch):        '''        Checks if next increment would generate a carry        '''        return ch == last(ch)    s = List(s)[::-1]    carry = True    try:        index = next(i for i,e in enumerate(s) if e.isalnum())    except stopiteration:        index = 0    while carry:        if index == len(s): #Add a character for Overflow            s.append(first(s[index - 1]))            break        carry =  True if islast(s[index]) else False        s[index] = incr(s[index])        index += 1    return ''.join(s[::-1])

示例用法

succ('2')       - > 3         succ('99')      - > 000       succ('zzz')     - > aaaa      succ('')        - > None      succ('abcd')    - > abce      succ('THX1138') - > THX1139   succ('<<koala>>') - > <<koalb>> succ('1999zzz') - > 2000aaa   succ('ZZZ9999') - > AAAA0000  succ('***')     - > **+

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