python实现将英文单词表示的数字转换成阿拉伯数字的方法

概述本文实例讲述了python实现将英文单词表示的数字转换成阿拉伯数字的方法。分享给大家供大家参考。具体实现方法如下：

本文实例讲述了python实现将英文单词表示的数字转换成阿拉伯数字的方法。分享给大家供大家参考。具体实现方法如下：

import re_kNown = {  'zero': 0,'one': 1,'two': 2,'three': 3,'four': 4,'five': 5,'six': 6,'seven': 7,'eight': 8,'nine': 9,'ten': 10,'eleven': 11,'twelve': 12,'thirteen': 13,'fourteen': 14,'fifteen': 15,'sixteen': 16,'seventeen': 17,'eighteen': 18,'nineteen': 19,'twenty': 20,'thirty': 30,'forty': 40,'fifty': 50,'sixty': 60,'seventy': 70,'eighty': 80,'ninety': 90  }def spoken_word_to_number(n):  """Assume n is a positive integer".assert _positive_integer_number('nine hundred') == 900assert spoken_word_to_number('one hundred') == 100assert spoken_word_to_number('eleven') == 11assert spoken_word_to_number('twenty two') == 22assert spoken_word_to_number('thirty-two') == 32assert spoken_word_to_number('forty two') == 42assert spoken_word_to_number('two hundred thirty two') == 232assert spoken_word_to_number('two thirty two') == 232assert spoken_word_to_number('nineteen hundred eighty nine') == 1989assert spoken_word_to_number('nineteen eighty nine') == 1989assert spoken_word_to_number('one thousand nine hundred and eighty nine') == 1989assert spoken_word_to_number('nine eighty') == 980assert spoken_word_to_number('nine two') == 92 # wont be able to convert this oneassert spoken_word_to_number('nine thousand nine hundred') == 9900assert spoken_word_to_number('one thousand nine hundred one') == 1901"""  n = n.lower().strip()  if n in _kNown:    return _kNown[n]  else:    inputWordArr = re.split('[ -]',n)  assert len(inputWordArr) > 1 #all single words are kNown  #Check the pathological case where hundred is at the end or thousand is at end  if inputWordArr[-1] == 'hundred':    inputWordArr.append('zero')    inputWordArr.append('zero')  if inputWordArr[-1] == 'thousand':    inputWordArr.append('zero')    inputWordArr.append('zero')    inputWordArr.append('zero')  if inputWordArr[0] == 'hundred':    inputWordArr.insert(0,'one')  if inputWordArr[0] == 'thousand':    inputWordArr.insert(0,'one')  inputWordArr = [word for word in inputWordArr if word not in ['and','minus','negative']]  currentposition = 'unit'  prevposition = None  output = 0  for word in reversed(inputWordArr):    if currentposition == 'unit':      number = _kNown[word]      output += number      if number > 9:        currentposition = 'hundred'      else:        currentposition = 'ten'    elif currentposition == 'ten':      if word != 'hundred':        number = _kNown[word]        if number < 10:          output += number*10        else:          output += number      #else: nothing special      currentposition = 'hundred'    elif currentposition == 'hundred':      if word not in [ 'hundred','thousand']:        number = _kNown[word]        output += number*100        currentposition = 'thousand'      elif word == 'thousand':        currentposition = 'thousand'      else:        currentposition = 'hundred'    elif currentposition == 'thousand':      assert word != 'hundred'      if word != 'thousand':        number = _kNown[word]        output += number*1000    else:      assert "Can't be here" == None  return(output)

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