c – uint8_t的类型乘以布尔值是什么？

概述从 standard开始,我试图了解表达式最终会是哪种类型： bool myBool;[...]uint8_t(255) * (myBool); 我保证myBool会被转换为uint8_t(a.k.a.unsigned char),或者整个结果可能是int吗？ 有用链接：bool to int conversion 从您链接到的文档： 5 Expressions 9 Many binary o 从 standard开始,我试图了解表达式最终会是哪种类型：

bool myBool;[...]uint8_t(255) * (myBool);

我保证myBool会被转换为uint8_t(a.k.a.unsigned char),或者整个结果可能是int吗？

有用链接：bool to int conversion

解决方法 从您链接到的文档：

5 Expressions

9 Many binary operators that expect operands of arithmetic or enumera-
tion type cause conversions and yIEld result types in a similar way.
The purpose is to yIEld a common type,which is also the type of the
result. This pattern is called the usual arithmetic conversions,
which are defined as follows:

…

–Otherwise,the integral promotions (conv.prom) shall be performed
on both operands.1)

和

4.5 Integral promotions

1 An rvalue of type char,signed char,unsigned char,short int,or
unsigned short int can be converted to an rvalue of type int if int
can represent all the values of the source type; otherwise,the source
rvalue can be converted to an rvalue of type unsigned int

…

4 An rvalue of type bool can be converted to an rvalue of type int,with
false becoming zero and true becoming one.

在您的情况下,LHS和RHS都将在算术运算之前被提升为int,结果将是int类型.

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