这是我在文件points.txt中的示例数据:
lexxo:30:1rey:40:2lion:40:2prince:50:3royal:50:3
所以当我从上面得到的是2d阵列(表)
player = {{(name),(points),(which var point earned on index)},{(...),(...),(...)}};
所以问题是,当我尝试循环打印文件中的所有数据.它只打印最新的一行.所以我想要打印所有这些
line_points = {}player_data = {{}}local rfile = io.open("points.txt","r")for line in rfile:lines() do playername,playerpoint,playerIDpoint = line:match("^(.-):(%d+):(%d+)$") player_data = {{playername,playerIDpoint}} line_points[#line_points + 1] = player_dataendfor i = 1,#player_data do player_checkname = player_data[i][1] -- Get Player name From Array for checking further player_checkpnt = player_data[i][3] -- Get Player ID Point From Array for checking further print(i..". name: "..player_data[i][1].." Point: ".. player_data[i][2] .. " ID: " .. player_data[i][3]);end解决方法 player_data总是有索引1,因为你没有向它添加项目,你将它们添加到line_points,其中#line_points是5,所以请改用它.
那是你想要的吗?
line_points = {}player_data = {{}} --I think you can delete it at all...--Because it is rewriting each time.local rfile = io.open("points.txt",playerIDpoint = line:match("^(.-):(%d+):(%d+)$") player_data = {playername,playerIDpoint} --I also remover double table here ^^^^^^^^^^^^^^^^^^^ line_points[#line_points + 1] = player_dataend--Here i checked counts--print('#pd='..#player_data)--print('#lp='..#line_points)--After it i decIDed to use line_points instead of player_datafor i = 1,#line_points do player_checkname = line_points[i][1] -- Get Player name From Array for checking further player_checkpnt = line_points[i][3] -- Get Player ID Point From Array for checking further print(i..". name: "..line_points[i][1].." Point: ".. line_points[i][2] .. " ID: " .. line_points[i][3]);end
输出:
1. name: lexxo Point: 30 ID: 12. name: rey Point: 40 ID: 23. name: lion Point: 40 ID: 24. name: prince Point: 50 ID: 35. name: royal Point: 50 ID: 3
更新:
在第一个循环中将player_data assignemnt更改为单个表后,它的计数总是为3.
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