c – 几个线程：抓住他们都完成工作的那一刻

概述我有几个线程,我需要抓住他们都完成工作的那一刻. 怎么做？ for (int i = 1; i < 3; i++) { std::thread threads1(countFile, i); i++; std::thread threads2(countFile, i); threads1.detach(); threads2.detach();}// wait 我有几个线程,我需要抓住他们都完成工作的那一刻.
怎么做？

for (int i = 1; i < 3; i++) {   std::thread threads1(countfile,i);   i++;   std::thread threads2(countfile,i);   threads1.detach();   threads2.detach();}// wait until all the threads run out---// to do next function ob object which uses by threads--

解决方法 考虑在for-block之外创建std :: thread对象并调用join()而不是detach()：

// empty (no threads associated to them yet)std::array<std::thread,2> threads1,threads2;for (int i = 0; i < 2; i++) {   threads1[i] = std::thread(countfile,i+1); // create thread   i++;   threads2[i] = std::thread(countfile,i+1); // create thread}// ...// join on all of themfor (int i = 0; i < 2; i++) {   threads1[i].join();   threads2[i].join();}// at this point all those threads have finished

不调用detach()意味着必须在调用std :: thread对象的析构函数之前调用join()(无论线程是否已经完成).

出于这个原因,我将std :: thread对象放在for-block之外.否则,必须在for-block内调用join().

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