设教学数据库中有3个关系？

select TNO,TN from T where TN like  '_伟%'

select TN from T where TNO='C5'

select T.TNO,T.TN,TC.CNO from T,TC where T.TNO=TC.TNO and T.TN='刘伟'

select TC.TNO,group by TC.CNO as ‘任课数’from TC,T where TC.TNO=T.TNO

and T.Dept='计算机' and  T.TNO in (select TNO from TC group by CNO havingcount(*)>2)

selcet TNO,TN from T where Prof  in （select Prof from T where TN='刘伟'）

select x.TN as姓名,x.Sal as 教师工资, y.Sal as刘伟的工资from T as x,T as y

where x.Sal>y.Sal and y.TN='刘伟'

第四问不太确定

1.SELECT COUNT(DISTINCT(学号）） FROM SC 2.SELECT 姓名 FROM S,SC WHERE S.学号=SC.学号 AND S.学号=1号 3.SELECT S.学号，姓名，课程名，成绩 FROM S,SC,C WHERE S.学号=SC.学号 AND SC.课程号=C.课程 AND 课程号=1号 4.SELECT S.学号，姓名 FROM S,SC WHERE S.学号=SC.学号 AND SC.课程=‘人工智能’ 5.SELECT MAX(成绩） FROM S,SC WHERE S.学号=SC.学号 AND S.学号=1号 6.SELECT 学号，姓名 FROM S WHERE SUBSTRING(姓名，3,2）=’月’ 7.SELECT 课程号，COUNT(*） FROM C,SC WHERE C.课程号=SC.课程号 8.SELECT S.学号，姓名 FROM S,SC,C WHERE S.学号=SC.学号 AND SC.课程号=C.课程号 AND C.成绩>80 9.SELECT DISTINCT（省区） FROM S WHERE S.系别=‘物理’ 10.SELECT * FROM S ORDER BY 系别 ASC，年龄 DSC 11.SELECT AVG(成绩 ） FROM C WHERE 课程号=2号 12.SELECT 学号，姓名 FROM S WHERE SUBSTRING(姓名，3,2）=’阳’

(1)select * from sales where qty between 1000 and 10000(2)select gname,price,type,qty from goods,sales where goods.g#=sales.g# and fact='青岛海尔集团' and s# in(select s# from shops where sname='北京东方大厦') (3)select g# from (select g#,max(a.aqty) from (select g#,AVG(QTY) as aqty from sales group by g#) as a group by g#) as b 本来这题用top 做简单、但是考虑到有销售量相同的、还是用上面这个 (4)delete from sales where qty is null (5)create view S_VIEW as select * from shops where addr like '南京路%'

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