如何用sed合并两行

用sed：

sed '$!Ns/\n//' filename

用awk：

awk '{if(NR%2==0) ORS="\n"else ORS=""print}' filename

linux文件中连续多行合并http://blog.uouo123.com/post/396.html

sed按条件多行合并为一行http://blog.uouo123.com/post/397.html

count1=`cat file1|wc -l`

count2=`cat file2|wc -l`

a=`expr $count1 - $count2`

if [ $a -gt 0 ]then

for((i=1i<=$count2i++))

do

x=${i}"p"

echo "`cat file1|sed -n "$x"` `cat file2|sed -n "$x"`" >>/result.log

done

count=`expr $count2 + 1`

for((j=$countj<=$count1j++))

do

y=${j}"p"

z=${count2}"p"

echo "`cat file1|sed -n "$y"` `cat file2|sed -n "$z"`" >>/result.log

done

elif [ $a -lt 0 ]then

for((i=1i<=$count1i++))

do

x=${i}"p"

echo "`cat file2|sed -n "$x"` `cat file1|sed -n "$x"`" >>/result.log

done

count=`expr $count1 + 1`

for((j=$countj<=$count2j++))

do

y=${j}"p"

z=${count1}"p"

echo "`cat file2|sed -n "$y"` `cat file1|sed -n "$z"`" >>/result.log

done

else

for((k=1k<=$count1k++))

do

f=${k}"p"

echo "`cat file1|sed -n "$f"` `cat file2|sed -n "$f"`" >>/result.log

done

fi

行数小的写在行数大的后面，同行的话直接第二个文件内容写在第一个后面