linux Shell Sed 命令 -- 如何 处理 XML 文件

1、思路，sed可以删除指定行内容，也可以在指定行添加内容

2、首先确定BB.Name所在行，如果有重复，需要增加head -1

r1=`grep -n "BB.Name" a.xml|awk -F: '{print $1}'|head -1`

3、<property>行号r2

((r2=r1-1))

4、</property>行号r3

((r3=r1+3))

5、删除r2和r3中间所有行

sed -i '${r2},${r3}d' a.xml

sed -i '5,8d' a.xml

sed -i '5d' a.xml

6、在r4行处读入s.txt内容

((r4=r1-2))

sed -i '$r4 r s.txt' a.xml

7、实例

#!/bin/sh

r1=`grep -n "BB.Name" a.xml|awk -F: '{print $1}'|head -1`

((r2=r1-1))

((r3=r1+3))

((r4=r1-2))

sed -i "${r2},${r3}d" a.xml

sed -i "${r4} r s.txt" a.xml

$cat test.sh

#!/bin/bash

if [ -z $1 ]then

echo 'USAGE:COMMAND FILENAME'

exit 0

fi

filename=record.txt

HOST=(`sed -n 's/.*>\(.*\)<\/host>/\1/p' $1`)

OIDG=(`sed -n 's/.*>\(.*\)<\/oidgroupname>/\1/p' $1`)

COMM=(`sed -n 's/.*>\(.*\)<\/communitystring>/\1/p' $1`)

DESC=(`sed -n 's/.*>\(.*\)<\/description>/\1/p' $1`)

FILE=(`ls -l $filename >/dev/null 2>&1 | awk '{print $8}'`)

if [ ! -z $FILE ]then

echo -e "host\t\toidgroupname\t\tcomm\t\tdesc" >$filename

fi

for((i=0i<${#HOST[@]}i++))do

echo -e "${HOST[i]}\t${OIDG[i]}\t${COMM[i]}\t\t${DESC[i]}" >>$filename

done

$./test.sh file

$cat record.txt

hostoidgroupnamecommdesc

192.168.1.1 CpuUtilization_MF public 192.168.1.1_CPUUtilizaton

192.168.1.2 CpuUtilization_MF public 192.168.1.2_CPUUtilizaton

192.168.1.3 CpuUtilization_MF public 192.168.1.3_CPUUtilizaton

192.168.1.4 CpuUtilization_MF public 192.168.1.4_CPUUtilizaton

192.168.1.5 CpuUtilization_MF public 192.168.1.5_CPUUtilizaton

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