java– 在php中登录服务器端时在android中进行会话处理

概述我正在尝试在android中执行会话处理过程.在这里,我已经通过android成功登录,现在我想要处理登录用户的会话.这是我的login_suer.java(android部分)packagecom.iwantnew.www;importjava.util.ArrayList;importjava.util.List;importorg.apache.http.NameValuePair;im

我正在尝试在android中执行会话处理过程.
在这里,我已经通过androID成功登录,现在我想要处理登录用户的会话.
这是我的login_suer.java(androID部分)

package com.iwantnew.www;import java.util.ArrayList;import java.util.List;import org.apache.http.nameValuePair;import org.apache.http.message.BasicnameValuePair;import org.Json.JsONException;import org.Json.JsONObject;import androID.app.Activity;import androID.app.ProgressDialog;import androID.content.Intent;import androID.os.AsyncTask;import androID.os.Bundle;import androID.util.Log;import androID.vIEw.VIEw;import androID.Widget.button;import androID.Widget.EditText;import androID.Widget.TextVIEw;public class login_user extends Activity{    private ProgressDialog pDialog;    JsONParser JsonParser = new JsONParser();    EditText login_email;    EditText login_password;    button signin;    TextVIEw error_msg;    private static String url_create_signin= "http://10.0.2.2/androID_iwant/login_user.PHP";    // JsON Node names            private static final String TAG_SUCCESS = "success";            public voID onCreate(Bundle savedInstanceState) {                super.onCreate(savedInstanceState);                setContentVIEw(R.layout.user_form);                // Edit Text                login_email = (EditText) findVIEwByID(R.ID.login_email);                login_password = (EditText) findVIEwByID(R.ID.login_password);                              signin = (button) findVIEwByID(R.ID.signin);                error_msg = (TextVIEw) findVIEwByID(R.ID.error_msg);                signin.setonClickListener(new VIEw.OnClickListener() {                    @OverrIDe                    public voID onClick(VIEw vIEw) {                        // creating new product in background thread                        new CheckLogin().execute();                    }                });            }            class CheckLogin extends AsyncTask<String, String, String> {                /**                 * Before starting background thread Show Progress Dialog                 * */                @OverrIDe                protected voID onPreExecute() {                    super.onPreExecute();                    pDialog = new ProgressDialog(login_user.this);                    pDialog.setMessage("Signing in..");                    pDialog.setIndeterminate(false);                    pDialog.setCancelable(true);                    pDialog.show();                }                /**                 * Creating product                 * */                protected String doInBackground(String... args) {                    //Building Parameters                    List<nameValuePair> params = new ArrayList<nameValuePair>();                    params.add(new BasicnameValuePair("email",login_email.getText().toString()));                    params.add(new BasicnameValuePair("password", login_password.getText().toString()));                    // getting JsON Object                    // Note that create product url accepts POST method                    JsONObject Json = JsonParser.makehttpRequest(url_create_signin,                            "POST", params);                    // check log cat fro response                    Log.d("Create Response", Json.toString());                    // check for success tag                    try {                        int success = Json.getInt(TAG_SUCCESS);                        if (success == 1) {                            // successfully created users                            Intent i = new Intent(getApplicationContext(), post_item.class);                            startActivity(i);                            // closing this screen                            finish();                        } else {                            // Failed to sign in                            error_msg.setText("Incorrect username/password");                        }                    } catch (JsONException e) {                        e.printstacktrace();                    }                    return null;                }                /**                 * After completing background task dismiss the progress dialog                 * **/                protected voID onPostExecute(String file_url) {                    // dismiss the dialog once done                    pDialog.dismiss();                }            }}@H_301_9@

现在我需要在这个java文件中启动会话处理的想法.
服务器端的代码如下：即login_user.PHP

<?PHPsession_start();// array for JsON response$response = array();if(isset($_POST['email']) && isset($_POST['password'])){    $email = $_POST['email'];    $password = $_POST['password'];// include db handler    require_once 'DB_Functions.PHP';    $db = new DB_Functions();     $user = $db->getUesrByEmailAndPassword($email, $password);      if ($user != false) {            // user found            // echo Json with success = 1            $response["success"] = 1;            $response["uID"] = $user["unique_ID"];            $response["user"]["name"] = $user["name"];            $response["user"]["email"] = $user["email"];            $response["user"]["created_at"] = $user["created_at"];            $response["user"]["updated_at"] = $user["updated_at"];            echo Json_encode($response);        } else {            // user not found            // echo Json with error = 1            $response["error"] = 1;            $response["error_msg"] = "Incorrect email or password!";            echo Json_encode($response);        }}?>@H_301_9@

上面这个PHP文件中使用的函数是getUesrByEmailAndPassword($email,$password)
在下面 ：

public function getUserByEmailAndPassword($email, $password) {        $result = MysqL_query("SELECT * FROM users WHERE email = '$email'") or dIE(MysqL_error());        // check for result         $no_of_rows = MysqL_num_rows($result);        if ($no_of_rows > 0) {            $result = MysqL_fetch_array($result);            $salt = $result['salt'];            $encrypted_password = $result['encrypted_password'];            $hash = $this->checkhashSSHA($salt, $password);            // check for password equality            if ($encrypted_password == $hash) {                // user authentication details are correct                //return $result;                session_start();                $_SESSION['clIEntID'] = $result[0];                $_SESSION['logged_in'] = TRUE;            }        } else {            // user not found            return false;        }    }@H_301_9@

请帮助我使我的代码工作.
任何帮助将不胜感激.
包含此类问题解决方案的任何链接对我都有帮助.谢谢！

解决方法:

据我所知,你的getUserByEmailAndPassword()在成功检查密码后永远不会返回实际的用户数据. //返回$result;被注释掉了. $user因此为null,客户端收到“电子邮件或密码不正确！”信息.

另一件事.要使PHP会话正常工作,客户端必须接收并记住其session_ID,并将其作为GET或cookie参数发送给每个请求.看看你的代码,我没有看到androID收到它的session_ID.见：http://www.php.net/manual/en/session.idpassing.php

顺便说一下,直接在POST中使用未经校对的$email进行SQL查询是一个坏主意.见：How can I prevent SQL injection in PHP?

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